Question

请您查看以下代码，让我知道如何修复代码的FROM econo WHERE ".$collm."=1") ;";部分以消除代码错误的禁用其余部分。我已尝试将"替换为'，但这会在代码中禁用我需要的$collm

<?PHP
include 'conconfig.php';
$con = new mysqli(DB_HOST,DB_USER,DB_PASS,DB_NAME);
$collm = $_POST['column'];
$query = "SELECT x, y  FROM  econo WHERE ".$collm."=1";
$results = $con->query($query);
$return = array();
if($results) {
while($row = $results->fetch_assoc()) {
    $return[] = array((float)$row['x'],(float)$row['y']);
}
}
$query2 = "CREATE TEMPORARY TABLE IF NOT EXISTS `charts_econo` (
          `id` int(12) NOT NULL AUTO_INCREMENT,
          `econo_sum_projects` decimal(12,7) NOT NULL,
          `econo_sum_powerline` decimal(12,7) NOT NULL,
          `econo_sum_roads` decimal(12,7) NOT NULL,
          `econo_sum_cost` decimal(12,7) NOT NULL,
           PRIMARY KEY (`id`)
          ) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AS(SELECT COUNT(project),
                                            SUM(powerline_length),
                                            SUM(road_length),
                                            SUM(cost_per_year)
                                            FROM  econo WHERE ".$collm."=1") ;";
$con->query($query2);
$con->close();
echo json_encode($return);
?>

Answer 1

只需替换：

FROM  econo WHERE ".$collm."=1") ;";

使用：

FROM econo WHERE $collm=1";

Answer 2

来自 FROM econo WHERE ".$collm."=1") ;";
到 FROM econo WHERE ".$collm."=1) ;";

如果你真的想把引号留在那里，那你只有一个太多了。

PHP-在AS SELECT上转义引用的问题

2 个答案: