Question

我有一个逐行读取csv文件的方法，并将每个记录放在一个列表中。我想测试一下这个方法。我所做的是创建了一个预期记录列表，然后我创建了一个csv文件，其中包含我在列表中创建的相同记录。我读了这个新创建的csv文件，并把它放在实际的记录列表中。然后我比较两个列表，但它给了我一个断言错误。

java.lang.AssertionError：expected：＆lt; [[Ljava.lang.String; @ 91b9b0]＆gt;但是＆lt; [[Ljava.lang.String; @ 1360c93]＆gt;

这是我的代码

String[] record = new String[] { "source", "name", "component", "10", "100", "10.5", "200", "15.5" }; 

MyReader reader = new MyReader();

@Test
public void readDataTest () throws FileNotFoundException
{
    List< String[] > expectedrecords = new ArrayList< String[] >();
    expectedrecords.add( record );

    List< String[] > actualrecords = new ArrayList< String[] >();
    generatetestCSV( dirPath + "\\Messages_Statistics.csv" );
    actualrecords = reader.readData( dirPath + "\\Messages_Statistics.csv" );

    Assert.assertEquals( expectedrecords, actualrecords );
}

private void generatetestCSV ( String fileName )
{
    try
    {
        FileWriter writer = new FileWriter( fileName );
        writer.append( "source" );
        writer.append( ',' );
        writer.append( "name" );
        writer.append( ',' );
        writer.append( "component" );
        writer.append( ',' );
        writer.append( "10" );
        writer.append( ',' );
        writer.append( "100" );
        writer.append( ',' );
        writer.append( "10.5" );
        writer.append( ',' );
        writer.append( "200" );
        writer.append( ',' );
        writer.append( "15.5" );
        writer.append( '\n' );
        writer.flush();
        writer.close();
    }
    catch ( IOException e )
    {
        e.printStackTrace();
    }
}

MyReader类中的readData是

  public List< String[] > readData ( String csvFile ) throws FileNotFoundException
{

    List< String[] > records = new ArrayList< String[] >();
    BufferedReader br = new BufferedReader( new FileReader( csvFile ) );
    String line = "";
    try
    {
        if ( csvFile != null )
        {
            if ( csvFile.contains( "Messages_Statistics" ) )
            {
                while ( ( line = br.readLine() ) != null )
                {
                    String[] record = line.split( "," );
                    if ( records.size() < LIMIT )
                        records.add( record );
                    else
                        break;
                }
            }

        }
    }
    catch ( FileNotFoundException e )
    {
        //logger.error( "Error in reading CSV file", e );
    }
    catch ( IOException e )
    {
        e.printStackTrace();
    }
    finally
    {
        if ( br != null )
        {
            try
            {
                br.close();
            }
            catch ( IOException e )
            {
                e.printStackTrace();
            }
        }
    }
    return records;
}

Answer 1

您无法使用Assert.assertEquals来比较List<String[]>。这不起作用：

List<String[]> expected = new ArrayList<>();
expected.add(new String[]{"foo", "bar"});
expected.add(new String[]{"baz", "qux"});

List<String[]> actual = new ArrayList<>();
actual.add(new String[]{"foo", "bar"});
actual.add(new String[]{"baz", "qux"});

Assert.assertEquals(expected, actual); // Fails!

你必须这样做：

List<String[]> expected = new ArrayList<>();
expected.add(new String[]{"foo", "bar"});
expected.add(new String[]{"baz", "qux"});

List<String[]> actual = new ArrayList<>();
actual.add(new String[]{"foo", "bar"});
actual.add(new String[]{"baz", "qux"});

assertEquals(expected.size(), actual.size());
for (int i = 0; i < expected.size(); i++) {
    for (int j = 0; j < expected.get(i).length; j++) {
        Assert.assertEquals(expected.get(i)[j], actual.get(i)[j]);
    }
}

Answer 2

Assert.assertEquals( expectedrecords, actualrecords );

这是比较不相同的列表对象实例。您需要遍历循环并对列表中的各个条目进行断言

更改Assert检查，如下所示

 Assert.assertEquals(expectedrecords.size(),actualrecords.size());
    int count = 0;

    for(String[] lineData: expectedrecords)
    {
        String[] actualRecordData = actualrecords.get(count);
        count++;

        Assert.assertEquals( lineData.length,actualRecordData.length);

        for(int i = 0; i < lineData.length; i++)
        {
            Assert.assertEquals( lineData[i],actualRecordData[i]);
        }
    }

Answer 3

编写一个将列表格式化为字符串的函数，然后比较字符串。如果他们匹配，那你很好。如果不这样做，则字符串diff比描述列表中的索引的异常更具可读性。特别是如果你在IntelliJ或Eclipse中运行测试，他们在那里格式化字符串以使差异非常明显。

用于读取csv文件的JUnit测试

3 个答案: