Python，写一个非常基本的闹钟

Question

我刚刚在python中写了一个非常基本的闹钟，当我在下午2:15准备了一些食物时警告我，但是我已经读到了某个时间，当其他程序正在处理时，睡眠时间缩短了，我该怎么办？用而代替？ 我目前的代码，它非常基本 -

import time
import winsound
time.sleep(370800)
winsound.Beep(1000,10000)

Answer 1

定期检查。下面的代码应该没问题。您可以根据需要调整timeout变量：

timeout = 10
target = time.time() + 370800

while True:
    diff = target - time.time()
    if diff < timeout:
        if diff > 0:  # highly unlikely that diff will go below 0 but just in case
            time.sleep(diff)
        break
    else:
        time.sleep(timeout)

winsound.Beep(1000,10000)