Question

我有两个初学者程序，都使用'while'功能，一个正常工作，另一个让我陷入循环。第一个项目是这个;

num=54
bob = True
print('The guess a number Game!')


while bob == True:
    guess = int(input('What is your guess?  '))

    if guess==num:
        print('wow! You\'re awesome!')
        print('but don\'t worry, you still suck')
        bob = False
    elif guess>num:
        print('try a lower number')
    else:
        print('close, but too low')

print('game over')``

它给出了可预测的输出;

The guess a number Game!
What is your guess?  12
close, but too low
What is your guess?  56
try a lower number
What is your guess?  54
wow! You're awesome!
but don't worry, you still suck
game over

但是，我也有这个程序，它不起作用;

#define vars
a = int(input('Please insert a number: '))
b = int(input('Please insert a second number: '))

#try a function
def func_tim(a,b):
    bob = True
    while bob == True:
        if a == b:
            print('nice and equal')
            bob = False
        elif b > a:
             print('b is picking on a!')
        else:
            print('a is picking on b!')
#call a function
func_tim(a,b)

哪些输出;

Please insert a number: 12
Please insert a second number: 14
b is picking on a!
b is picking on a!
b is picking on a!
...(repeat in a loop)....

有人可以告诉我为什么这些程序有所不同吗？谢谢！

Answer 1

在第二个示例中，用户没有机会在循环内输入新的猜测，因此a和b保持不变。

Answer 2

在第二个程序中，如果用户不相等，您永远不会给用户选择两个新号码的机会。将用户输入的行放在循环中，如下所示：

#try a function
def func_tim():
    bob = True
    while bob == True:
        #define vars
        a = int(input('Please insert a number: '))
        b = int(input('Please insert a second number: '))

        if a == b:
            print('nice and equal')
            bob = False
        elif b > a:
             print('b is picking on a!')
        else:
            print('a is picking on b!')
#call a function
func_tim()

Answer 3

在您的第二个程序中，如果b > a，您将返回循环，因为bob仍为true。你忘了让用户再次输入..试试这种方式

  def func_tim():
    while 1:
       a = int(input('Please insert a number: '))
       b = int(input('Please insert a second number: '))
       if a == b:
           print('nice and equal')
           break
       elif b > a:
           print('b is picking on a!')
       else:
           print('a is picking on b!')


func_tim()

Answer 4

如果不正确，您的第二个程序不允许用户重新输入猜测。将input放入while循环中。

其他提示：不要像variable == True那样进行检查，只需说while variable:。

初学者蟒蛇 - 卡在一个循环中

4 个答案: