为什么我不能将文字设置为Android？

Question

<嗨``嗨，我有一个计算器应用程序，屏幕上有数字和添加，乘法，清洁，子结构和除法按钮的按钮。但是当我打开并单击按钮时，他们无法在editText上进行更改。当我在keybord上写号码时，它进行了编辑。我该如何解决？

这里有我的java代码

private EditText screen; //textbox screen
private float numberBf; // save screen before pressing button operation
private String operation;
private ButtonClickListener btnClick;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    screen = (EditText) findViewById(editText);

    int idList[] = {R.id.button0,R.id.button,R.id.button2,R.id.button3,R.id.button4,
            R.id.button5,R.id.button6,R.id.button7,R.id.button8,R.id.button9, R.id.buttonAdd,R.id.buttonMul,
            R.id.buttonC, R.id.buttonDiv,R.id.buttonDot,R.id.buttonEq,R.id.buttonSub};

    for(int id:idList){
        View v = (View) findViewById(id);
        v.setOnClickListener(btnClick);
    }
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.main, menu);
    return true;
}
//new class
private class ButtonClickListener implements View.OnClickListener {
    public void onClick(View view){
        switch (view.getId()){
            case R.id.buttonC: //clear button
                screen.setText("0");
                numberBf = 0;
                operation = "";
                break;
            //adding function
            case R.id.buttonAdd:
                mMath("+");
                break;
            case R.id.buttonSub:
                mMath("-");
                break;
            case R.id.buttonMul:
                mMath("*");
                break;
            case R.id.buttonDiv:
                mMath("/");
                break;
            case R.id.buttonEq:
                mResult();
                break;
            default:
                String num = ((Button) view).getText().toString();
                getKeyboard(num);
                break;
        }
    }
}

public void mMath(String s){
    numberBf = Float.parseFloat(screen.getText().toString()); //save the screen
    operation = s; //save operation
    screen.setText("0"); //clear screen
}
public void mResult(){
    float numberFl = Float.parseFloat(screen.getText().toString());
    float result = 0;
    if(operation.equals("+"))
        result = numberFl + numberBf;
    if (operation.equals("-"))
        result =  numberBf - numberFl;
    if(operation.equals("*"))
        result = numberFl * numberBf;
    if (operation.equals("/"))
        result = numberBf / numberFl;

    screen.setText(String.valueOf(result));
}
public void getKeyboard(String str){
    String scrCurrent = screen.getText().toString();
    if (scrCurrent.equals("0"))
        scrCurrent = "";
    scrCurrent = str;
    screen.setText(str);
}

}

我的activity_main xml代码的一部分，第9个按钮和文本位置是

activity_main ：

<EditText android:layout_width="match_parent" android:layout_height="wrap_content" android:id="@+id/editText" android:text="0" android:layout_below="@+id/button0" android:layout_alignParentRight="true" android:layout_alignParentEnd="true" android:layout_marginTop="57dp" android:gravity="right" android:editable="true" /> <Button android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="9" android:id="@+id/button9" android:layout_below="@+id/button5" android:layout_toRightOf="@+id/button5" android:textStyle="bold" />

请帮助我谢谢

Answer 1

这应该有效：

screen = (EditText) findViewById(R.id.editText); 

Answer 2

screen = (EditText) findViewById(editText);

参数editText不是有效的资源标识符。在XML中你应该有

<EditText ...
   android:id="@+id/thetextid">

然后在你的代码中你应该

screen = (EditText) findViewById(R.id.thetextid);

Answer 3

您尚未实例化按钮单击侦听器。添加

btnClick = new ButtonClickListener();

在任何setOnClickListener(btnClick)来电之前

。