Question

我想创建一个简单的脚本，但我想允许用户使用$row->title代替$row['title']。

$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($con,"SELECT * FROM Persons");

while($row = mysqli_fetch_array($result)) {
  echo $row['FirstName'] . " " . $row['LastName']; //THIS IS THE PROBLEM, SEE BELOW
  echo "<br>";
}

mysqli_close($con);

我想将其设为echo $row->FirstName . " " . $row->LastName而不是echo $row['FirstName'] . " " . $row['LastName'];

Answer 1

使用 mysqli_fetch_object 代替mysql_fetch_array将结果集作为对象。

Answer 2

检查Manual以查找返回对象而不是数组的mysqli_fetch_object。使用以下代码

while($row = mysqli_fetch_object($result)) {
  echo $row->FirstName . " " . $row->LastName; 
  echo "<br>";
}

Answer 3

由于-> operator与对象一起使用，您需要以object形式而不是array or assoc array来获取数据。

$con=mysqli_connect("example.com","peter","abc123","my_db");
    // Check connection
    if (mysqli_connect_errno()) {
      echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }

    $result = mysqli_query($con,"SELECT * FROM Persons");

    while($row = mysqli_fetch_object($result)) {
      echo $row->FirstName . " " . $row->LastName; //THIS IS THE PROBLEM, SEE BELOW
      echo "<br>";
    }

    mysqli_close($con);

使用$ row-＆gt;元素而不是$ row [＆＃34;元素＆＃34;]的数据库查询（while或foreach）

3 个答案: