Question

如果我有以下列表

vowels = ["a","e","i","o","u"]

和另一个清单

words = ["happiness", "yellow"]

如何计算每个单词中元音的数量，即happiness = 3，yellow = 2？

Answer 1

使用列表理解：

>>> vowels = ["a","e","i","o","u"]
>>> words = ["happiness", "yellow"]
>>> [sum(c in vowels for c in word) for word in words]
[3, 2]

如果要在单词和出现之间进行映射，请使用字典理解：

>>> {word: sum(c in vowels for c in word) for word in words}
{'happiness': 3, 'yellow': 2}

将vowels转换为set会使其更有效。

Answer 2

data = [0]*len(words)                # Initializing the data list
for index, word in enumerate(words): # Iterating through the list of words
 for letter in list(word):
  if letter in vowels:               #checking if the letter is in vowels
   data[index] = data[index]+1
print data

数据现在包含与单词列表相同的索引对应的元音数。干杯! ：）

Python：计算字符串中列表项的出现次数

2 个答案: