XMPPFramework - 如何获取在线和离线朋友列表?

时间:2014-07-02 03:43:47

标签: ios xmpp xmppframework

如何在iOS中使用XMPPFramework获取在线和离线朋友列表?

我想向用户发送好友请求。那我该怎么做呢?有人可以为我分享一些示例代码吗?

谢谢。

1 个答案:

答案 0 :(得分:3)

通过使用这些方法,您将收到整个用户进入在线/离线,添加,删除,更新等的通知,使用这些方法可以更新您的联系人列表

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender didAddUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender didUpdateUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender didRemoveUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender
    didAddResource:(XMPPResourceMemoryStorageObject *)resource
          withUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender
 didUpdateResource:(XMPPResourceMemoryStorageObject *)resource
          withUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender
 didRemoveResource:(XMPPResourceMemoryStorageObject *)resource
          withUser:(XMPPUserMemoryStorageObject *)user

//添加好友

- (void)addContactWithUserName:(NSString *)userName andNickName:(NSString *)nickName;
{
    if(userName)
    {
        XMPPJID *jid = [XMPPJID jidWithString:[NSString stringWithFormat:@"%@@%@",userName,self.hostName]];
        if(nickName)
        {
            [_xmppRoster addUser:jid withNickname:nickName];
        }
        else
        {
            [_xmppRoster addUser:jid withNickname:nil];
        }
    }
else
{
    NSLog(@"missing userName");
}
}