我有一个可以像这样处理的数组:
ba = bytearray(fh.read())[32:]
size = int(math.sqrt(len(ba)))
我可以判断一个像素应该是黑色还是白色
iswhite = (ba[i]&1)==1
如何快速将我的1D字节数组转换为行长size
的2D numpy数组和(ba[i]&1)==1
的白色像素以及其他的黑色像素?我像这样创建数组:
im_m = np.zeros((size,size,3),dtype="uint8)
答案 0 :(得分:3)
import numpy as np
# fh containts the file handle
# go to position 32 where the image data starts
fh.seek(32)
# read the binary data into unsigned 8-bit array
ba = np.fromfile(fh, dtype='uint8')
# calculate the side length of the square array and reshape ba accordingly
side = int(np.sqrt(len(ba)))
ba = ba.reshape((side,side))
# toss everything else apart from the last bit of each pixel
ba &= 1
# make a 3-deep array with 255,255,255 or 0,0,0
img = np.dstack([255*ba]*3)
# or
img = ba[:,:,None] * np.array([255,255,255], dtype='uint8')
有几种方法可以完成最后一步。如果需要,请注意获得相同的数据类型(uint8
)。