Question

我正在开发一个Web应用程序并在我的Sercurity Context文件中收到错误：在此行找到多个注释： - 处理XML'javax / servlet / Filter'时出错。有关详细信息，请参阅错误日志 - spring-security-web jar（或其中一个依赖项）中的类不可用。你需要这些才能使用：javax.servlet.Filter

任何人都可以帮忙解决它。我已经发布了文件，POM和web.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/security   
http://www.springframework.org/schema/security/spring-security-3.1.xsd
    http://www.springframework.org/schema/beans 
http://www.springframework.org/schema/beans/spring-beans.xsd">


<security:authentication-manager>
    <security:authentication-provider>
        <security:user-service>
            <security:user name="John" authorities="admin"
                password="letmein" />
            <security:user name="Zog" authorities="admin"
                password="iamzog" />
        </security:user-service>
    </security:authentication-provider>
    <security:authentication-provider>
        <security:jdbc-user-service data-source-ref="dataSource" />
    </security:authentication-provider>
</security:authentication-manager>

<security:http use-expressions="true">  //this is where the error shows

    <security:intercept-url pattern="/createoffer" access="isAuthenticated()" />
    <security:intercept-url pattern="/docreate" access="isAuthenticated()" />
    <security:intercept-url pattern="/offercreated" access="isAuthenticated()" />
    <security:intercept-url pattern="/" access="permitAll" />
    <security:intercept-url pattern="/Home" access="permitAll" />
    <security:intercept-url pattern="/newaccount" access="permitAll" />
    <security:intercept-url pattern="/createaccount" access="permitAll" />
    <security:intercept-url pattern="/accountcreated" access="permitAll" />
    <security:intercept-url pattern="/static/**" access="permitAll" />
    <security:intercept-url pattern="/login" access="permitAll" />
    <security:intercept-url pattern="/offers" access="permitAll" />
    <security:intercept-url pattern="/**" access="denyAll" />
    <security:form-login login-page="/login"
        authentication-failure-url="/login?error=true" />
</security:http>

的pom.xml

<project xmlns="http://maven.apache.org/POM/4.0.0"    
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 
http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>Mic</groupId>
<artifactId>Mic</artifactId>
<version>0.0.1-SNAPSHOT</version>
<build>
  <sourceDirectory>src</sourceDirectory>
  <plugins>
    <plugin>
    <artifactId>maven-compiler-plugin</artifactId>
    <version>3.1</version>
    <configuration>
      <source>1.7</source>
      <target>1.7</target>
    </configuration>
  </plugin>
</plugins>
</build>
<dependencies>
<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-core</artifactId>
    <version>4.0.5.RELEASE</version>
</dependency>
<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-beans</artifactId>
    <version>4.0.5.RELEASE</version>
</dependency>
<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-context</artifactId>
    <version>4.0.5.RELEASE</version>
</dependency>
<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-jdbc</artifactId>
    <version>4.0.5.RELEASE</version>
</dependency>
<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-web</artifactId>
    <version>4.0.5.RELEASE</version>
</dependency>
<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-webmvc</artifactId>
    <version>4.0.5.RELEASE</version>
</dependency>
<dependency>
    <groupId>javax.servlet</groupId>
    <artifactId>jstl</artifactId>
    <version>1.2</version>
</dependency>
<dependency>
    <groupId>mysql</groupId>
    <artifactId>mysql-connector-java</artifactId>
    <version>5.1.31</version>
</dependency>
<dependency>
    <groupId>javax.validation</groupId>
    <artifactId>validation-api</artifactId>
    <version>1.1.0.Final</version>
</dependency>
<dependency>
    <groupId>org.hibernate</groupId>
    <artifactId>hibernate</artifactId>
    <version>3.5.4-Final</version>
    <type>pom</type>
</dependency>
<dependency>
    <groupId>org.hibernate</groupId>
    <artifactId>hibernate-validator</artifactId>
    <version>5.1.1.Final</version>
</dependency>
<dependency>
    <groupId>commons-validator</groupId>
    <artifactId>commons-validator</artifactId>
    <version>1.4.0</version>
</dependency>
<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-core</artifactId>
    <version>3.1.4.RELEASE</version>
</dependency>
<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-web</artifactId>
    <version>3.1.4.RELEASE</version>
</dependency>
<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-config</artifactId>
    <version>3.1.4.RELEASE</version>
</dependency>
</dependencies>
</project>

Web.xml中

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"       
 xmlns="http://java.sun.com/xml/ns/javaee"   
 xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"   
 xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>spring-tutorial-50</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<description></description>
<display-name>accounts</display-name>
<servlet-name>accounts</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>offers</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<description>Spring Database</description>
<resource-ref>
<description>DB Connection</description>
<res-ref-name>jdbc/sgc</res-ref-name>
<res-type>javax.sql.DataSource</res-type>
<res-auth>Container</res-auth>
</resource-ref>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
    classpath: com/Mic/config/dao-context.xml
    classpath: com/Mic/config/service-context.xml
    classpath: com/Mic/config/security-context.xml
    </param-value>
</context-param>
<filter>
`display-name>springSecurityFilterChain</display-name>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>

Answer 1

您正在使用Servlet api，但在您的pom.xml中，这不是servlet-api.jar的条目。添加

<dependency>
    <groupId>javax.servlet</groupId>
    <artifactId>servlet-api</artifactId>
    <version>2.5</version>
</dependency>

pom.xml中的

Answer 2

尝试将此依赖项添加到项目中。的javax.servlet servlet的API 3.0 提供

Answer 3

只需在项目Tomcat中添加Targeted Runtime即可。应该这样做。

Spring没有找到Maven依赖的jar

3 个答案: