在我的应用程序中,我为用户获取了一张个人资料图片,然后将其保存为序列化类作为字符串。
我使用下面的代码执行GZIP压缩和Base64,但是我不能像你在getProfilePicture()
方法中看到的那样做相反的事情:
private void saveBitmap(){
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
mBitmap.compress(Bitmap.CompressFormat.PNG, 100, byteArrayOutputStream);
byte[] byteArray = byteArrayOutputStream.toByteArray();
String bitmapContent = "";
try {
bitmapContent = FileHelpers.compressAndBase64(byteArray);
//later save it...
} catch (IOException e) {
e.printStackTrace();
Log.e(TAG, "Error converting bitmap to gzip and base64");
}
}
public static String compressAndBase64(byte[] byteArray)
throws IOException {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
GZIPOutputStream zos = new GZIPOutputStream(baos);
zos.write(byteArray);
zos.close();
byte[] bytes = baos.toByteArray();
return Base64.encodeToString(bytes, Base64.DEFAULT);
}
现在我想将它转换回Bitmap ...但到目前为止我还没有成功。
这些步骤将字符串从Base64解码回字节数组,然后解压缩字节数组并转换为Bitmap。
public Bitmap getProfilePicture(){
if(getProfilePhotoBase64() != null) {
byte[] decoded = Base64.decode(mProfilePhotoBase64.getBytes(), Base64.DEFAULT);
final int BUFFER_SIZE = 32;
ByteArrayInputStream is = new ByteArrayInputStream(decoded);
GZIPInputStream gis = null;
try {
gis = new GZIPInputStream(is, BUFFER_SIZE);
} catch (IOException e) {
e.printStackTrace();
}
StringBuilder string = new StringBuilder();
byte[] data = new byte[BUFFER_SIZE];
int bytesRead;
try {
while ((bytesRead = gis.read(data)) != -1) {
string.append(new String(data, 0, bytesRead));
}
} catch (IOException e) {
e.printStackTrace();
}
try {
gis.close();
is.close();
} catch (IOException e) {
e.printStackTrace();
}
byte[] byteArray = string.toString().getBytes();
Bitmap bitmap = BitmapFactory.decodeByteArray(byteArray, 0,byteArray.length);
if(bitmap != null) {
return bitmap;
} else {
return null;
}
}
return null;
}
这是我使用上述代码获得的错误消息:
--- SkImageDecoder::Factory returned null
我在PHP中可以很容易地做到这一点,但很难让它在Java中运行!
if(isset($_POST["photo"])) {
$photoContent = $_POST["photo"];
$photo = imap_base64 ($photoContent);
$photo = gzdecode($photo);
$filename = $_POST["username"].".png";
$dir = SITE_ROOT_PATH."/images/".$user."/".$filename;
file_force_contents($dir, $photo);
} else {
$filename = "NO_PROFILE_PHOTO";
}
答案 0 :(得分:1)
好的,我设法以这种方式修复了问题:
/**
* IMPORTANT NOTE!!!!!!!!!!!!!!
* String is first converted to byte array, then compressed using GZIP and then
* the resulting byte array is encoded to Base64.DEFAULT
* @return
*/
public String getProfilePhotoBase64() {
return mProfilePhotoBase64;
}
public Bitmap getProfilePicture(){
if(getProfilePhotoBase64() != null) {
byte[] decoded = Base64.decode(mProfilePhotoBase64.getBytes(), Base64.DEFAULT);
ByteArrayOutputStream bos = new ByteArrayOutputStream();
ByteArrayInputStream bis = new ByteArrayInputStream(decoded);
GZIPInputStream zis = null;
try {
zis = new GZIPInputStream(bis);
byte[] tmpBuffer = new byte[256];
int n;
while ((n = zis.read(tmpBuffer)) >= 0) {
bos.write(tmpBuffer, 0, n);
}
zis.close();
} catch (IOException e) {
e.printStackTrace();
}
Bitmap bitmap = BitmapFactory.decodeByteArray(bos.toByteArray(), 0
, bos.toByteArray().length);
if(bitmap != null) {
return bitmap;
} else {
return null;
}
}
return null;
}
答案 1 :(得分:0)
究竟是什么问题? compressAndBase64()将返回一个空字符串,因为boas.toByteArray()将返回0字节,因为boas刚刚创建,因此为空。你不需要创造一个蟒蛇。只需改变
return Base64.encodeToString(bytes, Base64.DEFAULT);
到
return Base64.encodeToString(byteArray, Base64.DEFAULT);