Question

我有一个活动，其中我有3个视图。点击一个按钮我隐藏了一个视图并显示另一个视图。但我怀疑是我不能回到上一个视图。我该怎么做。< / p>

例如：I am on view A, and i click a button so now view A is hidden and now B is displayed.Now if press back button A should be displayed again but this is not happening,y app is directly closing.

代码

switch (view.getId()) {
    case R.id.bt_continue_1:
        if (str_first_name.equals("") || str_last_name.equals("") || str_gender.equals("Select Gender") || str_religion.equals("Select Religion") || str_age.equals("Select Age")) {
              commonFunctions.showAlert(this, "INVALID", "Please fill all the mandatory details");
              personal_info.setVisibility(view.VISIBLE);
              professional_info.setVisibility(view.GONE);
              contact_info.setVisibility(view.GONE);
        } else {
              header.setText("Contact Info");
              personal_info.setAnimation(commonFunctions.animateLeft());
              contact_info.setAnimation(commonFunctions.animateRight());
              personal_info.setVisibility(view.GONE);
              professional_info.setVisibility(view.GONE);
              contact_info.setVisibility(view.VISIBLE);
        }
        break;

    case R.id.bt_continue_2:
        if (str_mobile.equals("") || str_state.equals("Select State") || strCity.equals("") || str_area.equals("") || str_address.equals("")) {
              commonFunctions.showAlert(this, "INVALID", "Please fill all the mandatory details");
              personal_info.setVisibility(view.GONE);
              professional_info.setVisibility(view.GONE);
              contact_info.setVisibility(view.VISIBLE);
        } else {
              header.setText("Professional Info");
              contact_info.setAnimation(commonFunctions.animateLeft());
              professional_info.setAnimation(commonFunctions.animateRight());
              personal_info.setVisibility(view.GONE);
              contact_info.setVisibility(view.GONE);
              professional_info.setVisibility(view.VISIBLE);
        }
        break;
//
//            if( code== KeyEvent.KEYCODE_BACK){
//
//            }

    case R.id.bt_save:
//                AddUpdateJobResource async = new AddUpdateJobResource (personal_info.this, "0", "34588A34-E969-4723-84FE-E5409B66A5B7", "", str_first_name, str_last_name, gender_id, age_substring, nationality_id, "IND", "INDIA", state_code, str_state, str_city, str_area, str_address, str_mobile, profession_id, religion_id, "2", months_substring, yrs_substring, "0.00", "0.00", "hssuraksha");
//                async.execute ();
        AddResources addResources = new AddResources();
        addResources.execute();
    }
}

请提出建议

Answer 1

我完全不了解你的问题。您的意思是设备的后退按钮或应用程序中的自定义设计按钮？在后一种情况下，您只需调用finish（） - 按下按钮时的Activity方法。

 case R.id.bt_back:
      // finish current view and go back to last view
      finish();

Answer 2

听起来您可能希望将视图A和视图B分成片段而不是隐藏/显示其特定数据。如果您仍想使用您的范例，则可以覆盖onBackPressed以在按下时显示视图A.

@Override
public void onBackPressed() {
   Log.d("YOUR_APP", "onBackPressed Called");  
   //Show/Hide stuff here 
}

Answer 3

后退按钮适用于活动，而不适用于视图。

默认的后退逻辑是（好吧，或多或少）＆＃39;关闭当前活动并返回之前的那个＆＃39;。

如果您想覆盖此行为，请将以下代码添加到您的活动中：

@Override
public void onBackPressed() {
   if (v1.getVisibility() == view.VISIBLE) {
       // hide v1, show v2, v3
       v1.setVisibility(view.GONE);
       v2.setVisibility(view.VISIBLE);
       v3.setVisibility(view.VISIBLE);
   }
   else if (v2.getVisibility() == view.VISIBLE) {
       // hide v2, show v1, v3
       v2.setVisibility(view.GONE);
       v1.setVisibility(view.VISIBLE);
       v3.setVisibility(view.VISIBLE);
   }
   else if (v2.getVisibility() == view.VISIBLE) {
       // close activity
       finish();
   }
}

或您的应用程序需要的任何其他后退按钮逻辑。

Answer 4

你的意思是你想从活动3导航到活动1吗？根据您的用例，您可以覆盖标准任务和Backstack行为。 http://developer.android.com/guide/components/tasks-and-back-stack.html

在背面按回到上一个视图

4 个答案: