var curtext = "View large image";
function changeSrc() {
if (curtext == "View large image") {
document.getElementById("boldStuff").innerHTML = "View small image";
curtext="View small image";
} else {
document.getElementById("boldStuff").innerHTML = "View large image";
curtext = "View large image";
}
}
var curimage = "cottage_small.jpg";
function changeSrc() {
if (curimage == "cottage_small.jpg") {
document.getElementById("myImage").src = "cottage_large.jpg";
curimage = "cottage_large.jpg";
} else {
document.getElementById("myImage").src = "cottage_small.jpg";
curimage = "cottage_small.jpg";
}
}
</script>
</head>
<body>
<!-- Your page here -->
<h1> Pink Knoll Properties</h1>
<h2> Single Family Homes</h2>
<p> Cottage:<strong>$149,000</strong><br/>
2 bed, 1 bath, 1,189 square feet, 1.11 acres <br/><br/>
<a href="#" onclick="changeSrc()"><b id="boldStuff" />View large image</a></p>
<p><img id="myImage" src="cottage_small.jpg" alt="Photo of a cottage" /></p>
</body>
我需要帮助,如何将两个参数作为一个函数放入?这意味着当您单击时,图像和文本都将更改。 谢谢! 比安卡
答案 0 :(得分:0)
function combined(curtext, curimage){
if(curtext == "View large image"){
document.getElementById("boldStuff").innerHTML = "View small image";
curtext="View small image";
}
else{
document.getElementById("boldStuff").innerHTML= "View small image";
curtext="View large image";
}
if(curimage == "cottage_small.jpg"){
document.getElementById("myImage").src="cottage_large.jpg";
curimage="cottage_large.jpg";
}
else{
document.getElementById("myImage").src="cottage_large.jpg";
curimage="cottage_small.jpg";
}
}
答案 1 :(得分:0)
创建一个调用它们的新函数,并将它们重命名为唯一的函数。
var changeCombined = function() {
changeTxt();
changeSrc();
};
function changeTxt() {
var node = document.getElementById("boldStuff");
if ( node.innerHTML == "View large image") {
node.innerHTML = "View small image";
} else {
node.innerHTML = "View large image";
}
}
function changeSrc() {
var image = document.getElementById("myImage");
if ( image.src == "cottage_small.jpg") {
image.src = "cottage_large.jpg";
} else {
image.src = "cottage_small.jpg";
}
}
这也消除了你对全局变量的依赖。