这是我得到的JSON数组:
[
{
"Name" : "Sachin",
"Age" : "41",
"Team" : "Mumbai"
},
{
"Name" : "Dravid",
"Age" : "42",
"Team" : "Rajasthan"
},
{
"Name" : "Yuvraj",
"Age" : "31",
"Team" : "Bangalore"
}
]
但是我需要通过“Age”属性对这个JSON数组desc进行排序。 我想要的JSON数组应如下所示:
[
{
"Name" : "Dravid",
"Age" : "42",
"Team" : "Rajasthan"
},
{
"Name" : "Sachin",
"Age" : "41",
"Team" : "Mumbai"
},
{
"Name" : "Yuvraj",
"Age" : "31",
"Team" : "Bangalore"
}
]
如何实现这一目标?
答案 0 :(得分:5)
var a = [
{
"Name" : "Sachin",
"Age" : "41",
"Team" : "Mumbai"
},
{
"Name" : "Dravid",
"Age" : "42",
"Team" : "Rajasthan"
},
{
"Name" : "Yuvraj",
"Age" : "31",
"Team" : "Bangalore"
}
];
a.sort(function(x,y){return y["Age"]-x["Age"]});
console.log(a);
答案 1 :(得分:2)
使用以下通用函数predicateBy按所需字段对数据进行排序
var data=[
{
"Name" : "Sachin",
"Age" : "41",
"Team" : "Mumbai"
},
{
"Name" : "Dravid",
"Age" : "42",
"Team" : "Rajasthan"
},
{
"Name" : "Yuvraj",
"Age" : "31",
"Team" : "Bangalore"
}
]
function predicatBy(prop){
return function(a,b){
if( a[prop] > b[prop]){
return 1;
}else if( a[prop] < b[prop] ){
return -1;
}
return 0;
}
}
//Usage
data.sort( predicatBy("age") );
console.log(data);
答案 2 :(得分:1)
var _ = require('underscore');
var data = ...your data...
console.log(_.sortBy(data, 'Age').reverse());
答案 3 :(得分:1)
试试这个:
var arr = [
{
"Name" : "Sachin",
"Age" : "41",
"Team" : "Mumbai"
},
{
"Name" : "Dravid",
"Age" : "42",
"Team" : "Rajasthan"
},
{
"Name" : "Yuvraj",
"Age" : "31",
"Team" : "Bangalore"
}
]
var prop = "Age"
arr.sort(function(a,b){
var cmp = -1
if (a.hasOwnProperty(prop) && b.hasOwnProperty(prop)){
var a_prop_value = parseFloat(a[prop])
var b_prop_value = parseFloat(b[prop])
if (isNaN(a_prop_value) || isNaN(b_prop_value)){
//string comp
cmp = a[prop].localeCompare(b[prop])
}else{
cmp = a_prop_value - b_prop_value > 0? 1 : a_prop_value - b_prop_value ==0? 0:-1
}
}
return cmp;
});
答案 4 :(得分:1)
天真的答案是使用Array.prototype.sort([compareFunction])。阻碍的方式:
function compareAgeProperty(a,b) {
return (parseInt(a.Age) < parseInt(b.Age)) ? -1 : 1;
}
var arr = [/* your array's data here */];
arr.sort(compareAgeProperty);
我建议你看看: https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Array/sort
您的Age属性是一个字符串,因此比较为字符串,表示'80'&lt;'9'=== true。解析该属性应该可以解决这个问题。