Question

不确定，但我觉得我错过了一些非常愚蠢的东西，我没有得到理想的结果。

查询非常简单

SELECT 
CASE 
WHEN 
GROUPING(DATEPART(YEAR,[ENTRY DATE]))=1 THEN 'GRAND TOTAL'
WHEN 
GROUPING(DATEPART(MONTH,[ENTRY DATE]))=1 THEN 'YEAR TOTAL'
WHEN 
GROUPING([ENTRY DATE])=1 
THEN 
CONVERT(CHAR(4), [ENTRY DATE], 100) + CONVERT(CHAR(4), [ENTRY DATE], 120) 
ELSE
CONVERT(VARCHAR,[ENTRY DATE])
END AS [ENTRY DATE],
COUNT([WORKTYPE]) AS [TOTAL VOLUME]
 FROM Assessment.INDIVIDUAL_MAIN
 WHERE [WorkType] IN ('QUERY','ASSESSMENT','DECLINE TO BRANCH')
GROUP BY ROLLUP(DATEPART(YEAR,[ENTRY DATE]),DATEPART(MONTH,[ENTRY DATE]),[ENTRY DATE])

所以我没有得到年度和月份的Concat，而是获得了空白

+-------------+-------+
| 2014-06-27  | 10757 |
+-------------+-------+
| 2014-06-28  |     2 |
| 2014-06-29  |     5 |
| 2014-06-30  |    16 |
| NULL        | 10780 |
| 2014-07-27  |     1 |
| NULL        |     1 |
| YEAR TOTAL  | 10781 |
| 2015-06-27  |     1 |
| NULL        |     1 |
| YEAR TOTAL  |     1 |
| GRAND TOTAL | 10782 |
+-------------+-------+

当我简单地写'年'或'总计'时，它运作良好，但我想显示月份和年份值而不是名称。

我做错了什么？任何见解都会有很大的帮助。

修改1 ：这是我的预期结果

+-------------+-------+
| 2014-06-27  | 10757 |
+-------------+-------+
| 2014-06-28  |     2 |
| 2014-06-29  |     5 |
| 2014-06-30  |    16 |
| 2014-06     | 10780 |
| 2014-07-27  |     1 |
| 2014-07     |     1 |
| 2014        | 10781 |
| 2015-06-27  |     1 |
| 2015-06     |     1 |
| 2015        |     1 |
| GRAND TOTAL | 10782 |
+-------------+-------+

Answer 1

好的，我想你想要这个：

SELECT 
  CASE 
    WHEN GROUPING(DATEPART(YEAR,[ENTRY DATE]))=1 
      THEN  DATENAME(yyyy,[ENTRY DATE])
    WHEN GROUPING(DATEPART(MONTH,[ENTRY DATE]))=1 
      THEN DATENAME(yyyy,[ENTRY DATE])+' - '+DATENAME(mm,[ENTRY_DATE])
    WHEN GROUPING([ENTRY DATE])=1 
      THEN CAST([ENTRY DATE] AS VARCHAR(50))
    ELSE 'GRAND TOTAL'
  END AS [ENTRY DATE],
  COUNT([WORKTYPE]) AS [TOTAL VOLUME]
FROM Assessment.INDIVIDUAL_MAIN
WHERE [WorkType] IN ('QUERY','ASSESSMENT','DECLINE TO BRANCH')
GROUP BY ROLLUP(DATEPART(YEAR,[ENTRY DATE]),DATEPART(MONTH,[ENTRY DATE]),[ENTRY DATE])

Answer 2

问题是ROLLUP会在摘要行的[ENTRY DATE]列中插入null。这就是为什么＆＃34;年＆＃34;和＆＃34; GRANT＆＃34; work，但引用[ENTRY DATE]的任何内容都为null。非摘要行（GROUPING(x) = 0）能够显示[ENTRY DATE]。

我不确定是否可以通过ROLLUP获得所需的结果。你可能需要以不同的方式去做。

这是一个可能的解决方案。它计算各种聚合，然后将结果结合在一起。它有点混乱，但是......它有效（我认为）。

--Daily
select CONVERT(varchar, [Entry Date]) [ENTRY DATE], 
COUNT(WORKTYPE) COUNT, 
CONVERT(varchar, [Entry Date]) sort
from Assessment.INDIVIDUAL_MAIN
group by [ENTRY DATE]

union

--Monthly
select convert(varchar, DATEPART(year, [Entry Date])) + '-' + convert(varchar, DATEPART(month, [Entry Date])), 
COUNT(WORKTYPE), 
convert(varchar, DATEPART(year, [Entry Date])) + '-' + RIGHT('0' + RTRIM(MONTH([ENTRY DATE])), 2) + '-40'
from Assessment.INDIVIDUAL_MAIN
group by DATEPART(year, [Entry Date]), DATEPART(month, [Entry Date])

union

--Yearly
select convert(varchar, DATEPART(year, [Entry Date])), 
COUNT(WORKTYPE), 
convert(varchar, DATEPART(year, [Entry Date])) + '-20-40'
from Assessment.INDIVIDUAL_MAIN
group by DATEPART(year, [Entry Date])

union

--Grand Total
select 'GRAND TOTAL', 
count(WorkType), 
'9999'
from Assessment.INDIVIDUAL_MAIN
order by sort

使用char值连接日期字段

2 个答案: