而不是这样做:
subject { response }
context 'when orphan' do
before do
post :create, asset: { parent_id: nil, uploaded_file: file }
end
it { should have_http_status 201 }
it { should redirect_to_location '/' }
it 'create a asset' do
expect { post :create, asset: { parent_id: nil, uploaded_file: file } }.to change(Asset, :count).by(1)
end
end
我希望能够做到这一点:
subject { response }
context 'when orphan' do
before do
post :create, asset: { parent_id: nil, uploaded_file: file }
end
it { should have_http_status 201 }
it { should redirect_to_location '/' }
it { should create_an(:asset) }
end
要做到这一点,我将不得不创建一个自定义匹配器:
RSpec::Matchers.define :create_an do |instance|
match do |actual|
#### ALL I NEED IS A WAY TO TRIGGER THIS LINE
# BEFORE THE BEFORE BLOCK
# before_before do
number_before = count_records
# end
##############################################
number_after = count_records
number_after - number_before == 1
end
def count_records
instance.to_s.classify.constantize.count
end
failure_message_for_should do |actual|
"..."
end
failure_message_for_should_not do |actual|
"..."
end
description do
"should create an #{instance.to_s}"
end
end
就像我说的,我需要做的就是运行:
number_before = count_records
在前一块之前,
before do
post :create, asset: { parent_id: nil, uploaded_file: file }
end
正在运行。这可能吗?有任何想法吗?任何钩子rspec为此提供了什么?
答案 0 :(得分:1)
我不知道如何实施您所要求的方法,但以下确实减少了一些重复。
context 'when orphan' do
let(:create) { post :create, asset: { parent_id: nil, uploaded_file: file } }
context 'the response' do
before { create }
subject { response }
it { is_expected.to have_http_status 201 }
it { is_expected.to redirect_to_location '/' }
end
it 'creates a asset' do
expect { create }.to change(Asset, :count).by(1)
end
end
答案 1 :(得分:1)
使用时间状态,添加额外的变量
time_b=0
do
number_before = count_records
time_b!=0
do
number_after = countrecords
before do
post :create, asset: { parent_id: nil, uploaded_file: file }
end
这应该可以解决问题。