Question

我有一个应用程序需要根据用户的动态选择从数据库中获取数据这是我的控制器代码：

$invoice_query = DB::table('invoices')->select('invoices.title', 'invoices.created_at', 'invoices.id', 'invoices.status', 'clients.first_name', 'clients.last_name')->join('clients', 'invoices.client_id', '=', 'clients.id');

    if( Input::has('status') && ( $status = Input::get('status') ) != "" )
    {
        $invoice_query->where('status', '=', $status);
    }

    if( Input::has('client') && ( $client_id = Input::get('client') ) != ""  )
    {
        $invoice_query->where('client_id', '=', $client_id);
    }


    $invoice_query->paginate(1);


    $data['invoices'] = $invoice_query->get();

    $data['total_invoices'] = 4;

    $this->layout->content    = View::make('backend.invoices.index', $data);

这个观点：

@foreach( $invoices as $invoice )
                        <tr>
                            <td>{{ $invoice->created_at }}</td>
                            <td>{{ $invoice->first_name }} {{ $invoice->last_name }}</td>
                            <td>{{ $invoice->title }}</td>
                            <td>
                                @if( $invoice->status == 0 )
                                    <span style="color: red; font-weight: bold;">Da pagare</span>
                                @else
                                    <span style="color: green; font-weight: bold;">Pagato</span>
                                @endif
                            </td>
                            <td>
                                <div class="btn-group">
                                    <a class="btn btn-warning" style="color: #FFF;" href="{{ url('invoices/'.$invoice->id.'/edit') }}">Modifica</a>
                                    <a class="btn btn-danger" style="color: #FFF;" href="{{ url('invoices/'.$invoice->id) }}">Cancella</a>
                                </div>
                            </td>
                        </tr>
                        @endforeach
                {{ $invoices->links() }}

问题是我得到的控制器代码：

Symfony \ Component \ Debug \ Exception \ FatalErrorException
Call to a member function links() on a non-object

我认为问题可能是：

$data['invoices'] = $invoice_query->get();

所以我删除了->get()但在这种情况下我得到了：

ErrorException

Trying to get property of non-object (View: /var/www/fatture/app/views/backend/invoices/index.blade.php)

无法弄清楚出了什么问题，能帮帮我吗？

NB：
如果我使用：

$data['invoices'] = Invoices::join('clients', 'invoices.client_id', '=', 'clients.id')->paginate( 1, array('invoices.title', 'invoices.created_at', 'invoices.id', 'clients.first_name', 'clients.last_name') );

一切正常但我不知道如何添加where

Answer 1

问题是将值赋给变量使用replace

删除 - ＆gt; get（）和paginate

 $data['invoices'] = $invoice_query->paginate(1);

Laravel 4 - 查询生成器 - 无法使用分页和clausole

1 个答案: