找到一个数组元素并将其设置为Ruby中的最后一个？

Question

在我的Ruby on Rails应用程序中，我有一个数组：

Car.color.values.map{|x| [x.text, x]}.sort 

这段代码给了我以下数组：

[["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Inny", "other"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"]]

现在我想找到这个元素：["Inny", "other"]并将其设置为数组的最后一个元素。 我怎么能在Ruby中做到这一点？

Answer 1

a = [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Inny", "other"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"]]
a.push(a.delete(["Inny", "other"]))
# => [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"], ["Inny", "other"]]

Answer 2

对于更通用的解决方案（当您不知道元素的确切值时），您可以使用partition，然后将答案连接起来：

arr = [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Inny", "other"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"]]
arr.partition { |k, v| v != "other" }.inject(:+)
# => [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"], ["Inny", "other"]] 

Answer 3

Array#rassoc搜索其元素也是数组的数组。

arr = [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], .....
arr.push(arr.delete(arr.rassoc("other")))

Answer 4

i = a.index(["Inny", "other"])
a.take(i) + a.drop(i + 1) << ["Inny", "other"]
=> [["Beżowy", "beige"], ["Biały", "white"], ["Brązowy", "brown"], ["Czarny", "black"], ["Czerwony", "red"], ["Fioletowy", "violet"], ["Grafitowy", "graphite"], ["Niebieski", "blue"], ["Perłowy", "pearl"], ["Srebrny", "silver"], ["Szary", "grey"], ["Zielony", "green"], ["Żółty", "yellow"], ["Inny", "other"]]