Question

我创建了一个方法，它将读取一个带有application / octet类型的文件，这里有一些代码。原始数据：

GTHHS;MEKID Interface;5496;2012-07-20; NM1;081;IN1;980898989;2001-01-15;Mr;Gaf;Uhkil;Uhkil,Gaf;PRI;Gaf

 $contents = file_get_contents($tmp_filename);
 $stringContents = explode(";", $contents);

现在它给了我这个输出：

Array
(
    [0] => GTHHS
    [1] => MEKID Interface
    [2] => 5496
    [3] => 2012-07-20
NM1
    [4] => 081
    [5] => IN1
    [6] => 980898989
    [7] => 2001-01-15
    [8] => Mr
    [9] => Gaf
    [10] => Uhkil
    [11] => Uhkil,Gaf
    [12] => PRI
    [13] => Gaf
PR1
    [14] => 081
    [15] => IN1
    [16] => 20730089
    [17] => 7 The Schooner
    [18] => Auhaas
    [19] => Huuula Ave
    [20] =>  
    [21] => Kishma
PR2
    [22] => 081
    [23] => IN1
    [24] => 232323233
    [25] => 400006
    [26] => HGD
    [27] => M
    [28] => M
    [29] => 2007-10-16
    [30] => 1976-03-31
);

如何将NM1，PR1作为数组的头部，如下所示：

Array (
     [NM1] = array(
            [0] => GTHHS 
            [1] => MEKID Interface 
            [2] => 5496 
            [3] => 2012-07-20
            )
);

我还计划将内部数组[0] - [3]设为json。

Answer 1

如果您按\n分解内容，则每行都以该标识符开头。如果你只是在该行中;爆炸并将其添加为子数组，那么就可以得到它。

这实际上看起来像一个普通的旧CSV文件，第一行带有ifentifier。如果是这样，尝试这样的事情：

$data = array();
if (($handle = fopen($filename, 'r')) !== FALSE)
{
    while (($row = fgetcsv($handle, 1000, ";", "\"", "\n")) !== FALSE)
    {
        $key = array_shift($row);
        $data[$key] = $row;
    }
    fclose($handle);
}

echo json_encode($data);

http://php.net/manual/en/function.str-getcsv.php

PHP数组包含字符串

1 个答案: