我有用户表和关注表 在下表中,我有用户ID - 和 - 关注者ID
我必须列出我必须使用用户和关注者的电子邮件ID的列表
我如何加入两个表
select f.USER_ID ,a.user_firstname, a.user_email ,f.Follow_Id
from bb_follow f, bb_user a
where a.user_id = f.User_Id and f.Active_Status=1 order by f.User_Id asc
(现在我想要关注者的信息 - 我可以添加的方式) -
答案 0 :(得分:1)
加入 bb_user 表两次,别名为 a (针对用户)和 b (针对关注者)。
select f.USER_ID, a.user_firstname, a.user_email,
f.FOLLOW_ID, b.user_firstname as follower_firstname, b.user_email as follower_email
from bb_follow f, bb_user a, bb_user b
where a.user_id = f.User_Id
and b.user_id = f.Follow_Id
and f.Active_Status=1
或使用ANSI连接:
select f.USER_ID, a.user_firstname, a.user_email,
f.FOLLOW_ID, b.user_firstname as follower_firstname, b.user_email as follower_email
from bb_follow f
join bb_user a on a.user_id = f.User_Id
join bb_user b on b.user_id = f.Follow_Id
where f.Active_Status=1
答案 1 :(得分:0)
试试这个:
SELECT f.USER_ID, a.user_firstname userName, a.user_email userEmail,
f.Follow_Id, b.user_firstname followerName, b.user_email followerEmail
FROM bb_follow f
LEFT JOIN bb_user a ON a.user_id = f.User_Id
LEFT JOIN bb_user b ON b.user_id = f.Follow_Id
WHERE f.Active_Status=1
ORDER BY f.User_Id ASC;
答案 2 :(得分:-1)
对你来说总体而言,语法错误,你需要加入
SELECT * FROM bb_follow f, 加入bb_user a ON f.User_id = a.user_id 在哪里f.Active_Status =' 1'
尝试,然后添加您的特定值