我花了一天时间玩deceze的答案,但我没有接近让它发挥作用。我可能有部分内容,但不确定如何在array_filter中获取递归。
My Array看起来像这样(样本):
Array
(
[name] => root
[ChildCats] => Array
(
[0] => Array
(
[name] => Air Conditioning
[ChildCats] => Array
(
[0] => Array
(
[name] => Ducted Air Conditioning
[ChildCats] => Array
(
[0] => Array
(
[name] => Supply & Install
[ChildCats] => Array
(
[0] => Array
(
[name] => Daiken
[S] => 6067
)
)
)
[1] => Array
(
[name] => Supply Only
[ChildCats] => Array
(
[0] => Array
(
[name] => Mitsubishi
[S] => 6026
)
)
)
)
)
[1] => Array
(
[name] => Split System Air Conditioning
[ChildCats] => Array
(
[0] => Array
(
[name] => Supply & Install
[ChildCats] => Array
(
[0] => Array
(
[name] => Daiken
[S] => 6067
)
[1] => Array
(
[name] => Fujitsu Split Air Conditioning Systems
[S] => 6464
)
[2] => Array
(
[name] => Mitsubishi Electric Split Air Conditioning Systems
[S] => 6464
)
)
)
)
)
)
)
[1] => Array
(
[name] => Appliance / White Goods
[ChildCats] => Array
(
[0] => Array
(
[name] => Clearance
[S] => 6239
)
[1] => Array
(
[name] => Cooktops
[ChildCats] => Array
(
[0] => Array
(
[name] => Ceramic Cooktops
[S] => 6239
)
[1] => Array
(
[name] => Element Cooktops
[S] => 6067
)
[2] => Array
(
[name] => Gas Cooktops
[S] => 6239
)
[3] => Array
(
[name] => Induction Cooktops
[S] => 6239
)
)
)
)
)
现在让我说我尝试将数组的各个部分提取到以下密钥对:
S => 6067。
我希望结果如下:
Array
(
[name] => root
[ChildCats] => Array
(
[0] => Array
(
[name] => Air Conditioning
[ChildCats] => Array
(
[0] => Array
(
[name] => Ducted Air Conditioning
[ChildCats] => Array
(
[0] => Array
(
[name] => Supply & Install
[ChildCats] => Array
(
[0] => Array
(
[name] => Daiken
[S] => 6067
)
)
)
)
)
[1] => Array
(
[name] => Split System Air Conditioning
[ChildCats] => Array
(
[0] => Array
(
[name] => Supply & Install
[ChildCats] => Array
(
[0] => Array
(
[name] => Daiken
[S] => 6067
)
)
)
)
)
)
)
[1] => Array
(
[name] => Appliance / White Goods
[ChildCats] => Array
(
[0] => Array
(
[name] => Cooktops
[ChildCats] => Array
(
[0] => Array
(
[name] => Element Cooktops
[S] => 6067
)
)
)
)
)
)
)
我无法理解的是我应该创建一个新数组还是使用数组过滤器。
使用deceze代码我已经使用以下内容进行了搜索:
function recursive_assoc_in_array(array $haystack, array $needle, $childKey = 'ChildCats') {
if (array_intersect_assoc($haystack, $needle)) {
echo "Found via array_intersect_assoc ".$haystack[name]."\n";
return true;
}
foreach ($haystack[$childKey] as $child) {
if (recursive_assoc_in_array($child, $needle, $childKey)) return true;
}
return false;
}
但如果我尝试处理,
$array = array_filter($array, function (array $values) {
return recursive_assoc_in_array($values, array('S' => '6067'));
});
我得到原始数组,这使我认为我必须在array_filter查询上运行递归。
此时我只是空白。
此外,数组键需要在生成的新数组上重新编制索引。有什么想法吗?
- 额外的7/7/14
如果我尝试从旧数组构建一个新数组怎么样?
我正在尝试:
function exploreArrayandAdd($Array) {
if ($Array['ChildCats']) {
foreach ($Array['ChildCats'] as $key => $value) {
$NewArray['ChildCats'][] = exploreArrayandAdd($value);
}
} else {
if ($Array['S'] == 6026) {
//echo "1";
return $Array;
}
}
}
但是无法弄清楚如何将新数组传递出函数?
尝试删除不匹配的分支:
function exploreArray(&$Array) {
if ($Array['ChildCats']) {
foreach ($Array['ChildCats'] as $key => $value) {
$result = exploreArray($Array['ChildCats'][$key]);
if ($result === false)
unset($Array['ChildCats'][$key]);
}
} else {
// print_r($Array);
if ($Array['S'] == 6026) {
return true;
} else {
unset($Array);
return false;
}
}
//if ($NoChildCat==true) print_r($Array);
}
但我认为这是错误的方式,因为它在阵列的底部工作,但没有回到顶部,因为兄弟姐妹的结果是真的。 这也不会重新索引数组键。
答案 0 :(得分:0)
function recursive_array_filter(array $array, $childKey, callable $test) {
if (isset($array[$childKey]) && is_array($array[$childKey])) {
foreach ($array[$childKey] as $key => &$child) {
if (!$child = recursive_array_filter($child, $childKey, $test)) {
unset($array[$childKey][$key]);
}
}
if (!$array[$childKey]) {
unset($array[$childKey]);
}
}
return !empty($array[$childKey]) || $test($array) ? $array : [];
}
$array = recursive_array_filter($array, 'ChildCats', function (array $array) {
return array_intersect_assoc($array, ['S' => 6026]);
});
用语言表达算法:首先下降到数组中,然后跟随所有ChildCats
个分支到它们的末尾。在每个级别中,如果值匹配您的测试或(如果他们有孩子),或者您返回一个空的数组(如果您还是false
,则返回给调用者的值)喜欢)。如果某个孩子变空,则用unset
修剪它。
我已将测试作为回调函数实现,以实现代码的最佳可重用性。