如何解开这个表格

Question

我创建了一个临时表，我想将其取消，但我不断收到如下错误消息：    消息156，第15级，状态1，第196行    关键字＆＃39;附近的语法不正确

我的临时表如下：

档案订单号T_Code Routine_Labour Variable_Labour

我想把它转到下面：

我使用了以下脚本：

Select 
Dossier,
Order_Number,
T_Code,
Labour_Type,
Amount

from 
#LabourSplit

Unpivot 
(
 Amount for Labour_Type in (Routine_Labour, Variable_Labour)
 ) as LabourSplit_U

一旦我运行此脚本，就会弹出错误消息。即使我在临时表和脚本中注释掉了两列，但仍然存在错误消息。

Select 
Dossier,
--Order_Number,
--T_Code,
Labour_Type,
Amount

from 
#LabourSplit

Unpivot 
(
 Amount for Labour_Type in (Routine_Labour, Variable_Labour)
 ) as LabourSplit_U

Answer 1

我认为CROSS APPLY VALUES比UNPIVOT

更容易使用和理解

SELECT Dossier
      ,Order_Number
      ,T_Code
      ,Labour_Type
      ,Amount
FROM #LabourSplit
     CROSS APLLY (
         VALUES (Routine_Labour, 'Routine_Labour')
               ,(Variable_Labour, 'Variable_Labour')
     ) AS CA1(Amount, Labour_Type)

Answer 2

试试这个：

Select 
Dossier,
Order_Number,
T_Code,
Labour_Type,
Amount
FROM
(
  Select 
  Dossier,
  Order_Number,
  T_Code,
  Routine_Labour, 
  Variable_Labour
  from #LabourSplit
) a
Unpivot 
(
  Amount for Labour_Type in (Routine_Labour, Variable_Labour)
) as LabourSplit_U

SQL Fiddle

结果：

| DOSSIER | ORDER_NUMBER | T_CODE |     LABOUR_TYPE | AMOUNT |
|---------|--------------|--------|-----------------|--------|
|    1234 |         5678 |      1 |  Routine_Labour |     10 |
|    1234 |         5678 |      1 | Variable_Labour |     20 |
|    1234 |         3434 |      1 |  Routine_Labour |     20 |
|    1234 |         3434 |      1 | Variable_Labour |     70 |
|    1234 |         5671 |      1 |  Routine_Labour |     30 |
|    1234 |         5671 |      1 | Variable_Labour |     10 |
|    1234 |         3422 |      1 |  Routine_Labour |     40 |
|    1234 |         3422 |      1 | Variable_Labour |     40 |
|    1234 |         1122 |      1 |  Routine_Labour |     11 |
|    1234 |         1122 |      1 | Variable_Labour |     30 |

但是，据我所知，UNPIVOT在完整版本的SQL Server中受支持。如果您有紧凑版或其他免费版本，则需要使用UNION ALL：

Select 
Dossier,
Order_Number,
T_Code,
'Routine_Labour' AS Labour_Type,
Routine_Labour AS Amount
FROM LabourSplit
UNION ALL 
Select 
Dossier,
Order_Number,
T_Code,
'Variable_Labour' AS Labour_Type,
Variable_Labour AS Amount
FROM LabourSplit
ORDER BY 1,2,3

选中此SQL Fiddle

结果：

| DOSSIER | ORDER_NUMBER | T_CODE |     LABOUR_TYPE | AMOUNT |
|---------|--------------|--------|-----------------|--------|
|    1234 |         1122 |      1 |  Routine_Labour |     11 |
|    1234 |         1122 |      1 | Variable_Labour |     30 |
|    1234 |         3422 |      1 | Variable_Labour |     40 |
|    1234 |         3422 |      1 |  Routine_Labour |     40 |
|    1234 |         3434 |      1 |  Routine_Labour |     20 |
|    1234 |         3434 |      1 | Variable_Labour |     70 |
|    1234 |         5671 |      1 | Variable_Labour |     10 |
|    1234 |         5671 |      1 |  Routine_Labour |     30 |
|    1234 |         5678 |      1 |  Routine_Labour |     10 |
|    1234 |         5678 |      1 | Variable_Labour |     20 |