Question

现在，我的旋转图像在我的目标图像的左侧和顶部被对齐。我想要的行为是旋转图像的中心在目标图像上居中。旋转程度是动态的。 $ center_pt是我目的地的中心点。我一直在网上寻找一天半，但必须有办法！

$destination_image = 960; //960px x 960px
rotated image = 640px x 640px; // ($rotate & $rotate_me, same thing)
$center_pt = center of destination image

$rotate_me = imagecreatefrompng("myimage.png"); 
$rotate = imagerotate($rotate_me, $dynamicdegree),0);
imagesettile($im, $rotate);
imagefilledellipse($destination_image, $center_pt, $center_pt, $outer_outer_diameter, $outer_outer_diameter,     IMG_COLOR_TILED);

抱歉，我准备了一张图片与您分享，但没有足够的声誉发布。

Answer 1

很难弄清楚如何在旋转之后将图像居中，因为它一直向右对齐。这是我所做的，在删除一个更详细的解决方案后，工作完美！

  $src = imagerotate($rotate,$yournumber,$transColor); //rotated my image
  imagesavealpha($src, true); // alpha thing otherwise there was a black polygon around image

  //the rotation makes your image bigger, usually, so you need to find the new width and height

  $src_x = ImageSX($src); //find out new x width
  $src_y = ImageSY($src); //find out new y height

  $wantedWidth = 640;  //this is the width I want my completed image to be
  $wantedHeight = 640; //this is the height I want my completed image to be

  $src_widthx = $src_x/2 - $wantedWidth/2;  // divide each by 2 and then subtract desired end width from wider rotated width
  $src_heighty = $src_y/2 - $wantedHeight/2;  // and again for height

imagecopy($im, $src, 0, 0, $src_widthx, $src_heighty, 640, 640);  //notice I'm no longer using imagefilledellipse here as imagecopy seems to be more specifically for centering things

Imagerotate然后与目标图像的中心对齐

1 个答案: