Question

我有2个活动A，B，两个活动都使用onActivityResult()。

过程：

onActivityResult()罚款。
我在活动B中有两个onActivityResult()（在下面的代码中显示）。第一个作为可点击的TextView，它也正常工作。另一个是Button。

我面临的问题是在Button中，它假设从B的子活动中带来一个Bitmap并在B中的ImageView中显示。当我点击按钮时，它会转到活动A的onActivityResult()。

startActivityForResult()：

int capSig = arg0.getId();
if(capSig == R.id.capSig)      //Button  which takes me to sub-activity of B
{
    Intent goToCapSignatures = new Intent(this, CaptureSignature.class);
    startActivityForResult(goToCapSignatures, GET_SIG);

}

我如何将ByteArray更改为位图并将位图发送到活动B：

Bitmap returnedBitmap = Bitmap.createBitmap(mContent.getWidth(),
                 mContent.getHeight(), Bitmap.Config.ARGB_8888);
         Canvas canvas = new Canvas(returnedBitmap);
         Drawable bgDrawable = mContent.getBackground();
         if (bgDrawable != null)
             bgDrawable.draw(canvas);
         else
             canvas.drawColor(Color.WHITE);
         mContent.draw(canvas);

         ByteArrayOutputStream bs = new ByteArrayOutputStream();
         returnedBitmap.compress(Bitmap.CompressFormat.PNG, 50, bs);
         byte[] byteArray = bs.toByteArray();
         Bitmap bitmap = BitmapFactory.decodeByteArray(byteArray , 0, byteArray.length);



         //send the captured signature to Check and Operations page
         Intent returncapSigIntent = new Intent();
         returncapSigIntent.putExtra("signature",bitmap);
        setResult(RESULT_OK, returncapSigIntent);
        finish();

onActivityResult()：

protected void onActivityResult(int requestCode, int resultCode, Intent data) 
{
      if (requestCode == GET_NOTES)        // For textview (working fine)
      {
        if(resultCode == RESULT_OK)
        {
            if (data.hasExtra("notes ready")) 
        {
            String readyNotes = data.getExtras().getString("notes ready");
            showNotesFromNotesClass.setText(readyNotes);
        }
      }

      if (requestCode == GET_SIG)         // for Button - this isn't being  
                                                      called instead 
      {
          if(resultCode == RESULT_OK)
          {
            if (data.hasExtra("signature")) 

                //display Bitmap in an ImageView

                capturedSigImageFromCapSigclass = (Bitmap) data.getExtras().get("signature");
                imgSig.setImageBitmap(capturedSigImageFromCapSigclass);
            }
          }

    }
      }
}

onActivityResult() :(这被称之为。

protected void onActivityResult(int requestCode, int resultCode, Intent data) 
{

      if (resultCode == RESULT_OK && requestCode == REQUEST_APPLIANCE) {
        if (data.hasExtra("selected appliance")) 
        {
            String selectedAppType = data.getExtras().getString("selected appliance");
            tvApplianceType.setText(selectedAppType);
          Toast.makeText(this, data.getExtras().getString("selected appliance"),
            Toast.LENGTH_SHORT).show();
        }
      }
    }

我确定我正在做一些工作。如果我出错了，请给我一些指示或指导。我将非常感激，因为我已经在这个逻辑上度过了几天而没有到达任何地方。感谢

Answer 1

您只需更改每个活动的requestCode值，以确保只调用一个。

requestsCode只是int常量，它们只是代表！

private static final int GET_NOTES = 0;

...

private static final int GET_SIG = 1;
...

private static final int REQUEST_APPLIANCE = 2;

这应该足以使结果多样化

错误的onActivityResult（）被调用

1 个答案: