为什么dart编辑器仍在运行

Question

我对dart编辑器非常困惑，它是如何工作的。当我运行这个应用程序时

import 'dart:isolate';
import 'package:dbcrypt/dbcrypt.dart';
import 'dart:async';

main() {

  //ReceivePort receivePort = new ReceivePort();
  var receivePortPw = new ReceivePort();
  receivePortPw.listen((msg) {
     print(msg); 
  });


  Future<Isolate> f = Isolate.spawn(ReturnHashedPassword, receivePortPw.sendPort);
  f.then((Isolate i) {
    print('Print1 -> ' + new DBCrypt().hashpw('Password', new DBCrypt().gensalt()));
    print('Print2 -> ' + new DBCrypt().hashpw('Password', new DBCrypt().gensalt()));
  });
}

void ReturnHashedPassword(SendPort sendPort)
{
    print('ok');
    ReceivePort receivePort = new ReceivePort();
    sendPort.send('Isolate -> ' + new DBCrypt().hashpw('Password', new DBCrypt().gensalt()));
    print('done');
}

编辑看起来，它仍然在运行。看看下面的打印屏幕，终止按钮（红色方块按钮）没有禁用，它记得我，当我运行一个http服务器时，这个按钮不会禁用，直到我手动执行它。

为什么终止按钮在输出后不会禁用？它只是I / O应用程序，它不是网络服务器。

Answer 1

你正在听跑步隔离。你可以关闭它的端口或简单地杀死它：

import 'dart:isolate';
import 'package:dbcrypt/dbcrypt.dart';
import 'dart:async';

main() {

  //ReceivePort receivePort = new ReceivePort();
  var receivePortPw = new ReceivePort();
  receivePortPw.listen((msg) {
     print(msg);
     receivePortPw.close();//stop listening.
  });


  Future<Isolate> f = Isolate.spawn(ReturnHashedPassword, receivePortPw.sendPort);
  f.then((Isolate i) {
    print('Print1 -> ' + new DBCrypt().hashpw('Password', new DBCrypt().gensalt()));
    print('Print2 -> ' + new DBCrypt().hashpw('Password', new DBCrypt().gensalt()));
    //i.kill(); // not nice...
  });
}

void ReturnHashedPassword(SendPort sendPort)
{
    print('ok');
    ReceivePort receivePort = new ReceivePort();
    sendPort.send('Isolate -> ' + new DBCrypt().hashpw('Password', new DBCrypt().gensalt()));
    print('done');
}