Question

我写了一个简短的函数，它检测矩阵键盘上按下的按钮并写下他的id（48个按钮，因此ID为0 - 47）。

问题是，它只是检测到ButtonID 0是正确的，其他的被检测得非常难看，就像ButtonID 1位于ButtonID 3的位置一样;

我无法在该代码中发现任何问题...我已初始化（我希望），我正在检测它们......但它们仍然有错误的ID。感谢您的任何回复或解决方案。

实际上我正在代码中测试ButtonID10 我为我的6（cols）x8（行）矩阵键盘编写了我的代码：

#include <avr/io.h>

// PIN's Init definitions
#define O(DIR,PIN) DIR |= (1 << PIN) // Marks PIN as output pin
#define OX(DIR) DIR = 0xFF // Makes all PINs as output pins
#define I(DIR,PIN) DIR &= ~(1 << PIN) // Makes PIN as input pin
#define IX(DIR) DIR = 0x00 // Makes all PINs as input pins
// PIN's SET definitions
#define H(PORT,PIN) PORT |= (1<<PIN) // Makes PIN 5V
#define HX(PORT) PORT = 0xFF // Makes all PINs 5V
#define L(PORT,PIN) PORT &= ~(1<<PIN) // Makes PIN 0V
#define LX(PORT) PORT = 0x00 // Makes all PINs 0V
#define S(PORT,BIN) PORT = BIN // Makes PINs activated from binary pattern
// PIN's GET definitions
#define GET(GPIN,PIN) GPIN & (1<<PIN) // Reads digital value on PIN
#define GET2(GPIN,BIN) GPIN & BIN // Reads digital value of binary defined PIN

int cols = 6;
int rows = 8;
int binary[8] = {0b00000001,0b00000010,0b00000011,0b00000100,0b00000101,0b00000110,0b00000111,0b00001000};

int checkKeys();
void initPins();

int main(void)
{
    initPins();

    //TESTS
    OX(DDRH);
    L(PORTH,PH1);
    //TESTS

    while (1){
        if (checkKeys() == 10){
            H(PORTH,PH1);
        }else{
            L(PORTH,PH1);
        }
    }

    return 0;
}

void initPins(){
    OX(DDRK);
    IX(DDRF);
}



int checkKeys(){
    for (int x = 0; x < rows; x++){
        S(PORTK,binary[x]);
        for (int y = 0; y < cols; y++){
            if (GET2(PINF,binary[y])){
                return (x*cols + y);
            }
        }
    }
    return -1;
}

Answer 1

好的，我终于弄明白为什么它不起作用。代码是正确的，但我在int类型数组'binary'中犯了一个错误 - 第一个错误是它们是octals，第二个是我在计算，而不是移动值。

但是现在又出现了另一个问题......程序没有检测到最后2个（0,1,2,3是可检测的，4,5不是）。

相信我 - 我试图解决这个问题，我甚至重新整理了所有按钮＆amp;零电阻，但任何工作。 THX

#include <avr/io.h>

// PIN's Init definitions
#define O(DIR,PIN) DIR |= (1 << PIN) // Marks PIN as output pin
#define OX(DIR) DIR = 0xFF // Makes all PINs as output pins
#define I(DIR,PIN) DIR &= ~(1 << PIN) // Makes PIN as input pin
#define IX(DIR) DIR = 0x00 // Makes all PINs as input pins
// PIN's SET definitions
#define H(PORT,PIN) PORT |= (1<<PIN) // Makes PIN 5V
#define HX(PORT) PORT = 0xFF // Makes all PINs 5V
#define L(PORT,PIN) PORT &= ~(1<<PIN) // Makes PIN 0V
#define LX(PORT) PORT = 0x00 // Makes all PINs 0V
#define S(PORT,BIN) PORT = BIN // Makes PINs activated from binary pattern
#define INV(PORT) PORT = ~PORT // Inverts all PINs values
// PIN's GET definitions
#define GET(GPIN,PIN) GPIN & (1<<PIN) // Reads digital value on PIN
#define GET2(GPIN,BIN) GPIN & BIN // Reads digital value of binary defined PIN

// Definitions for KEYBOARD ROWS and COLS
#define KEYBOARD_ROW PORTK
#define KEYBOARD_COL PINF

// Some important variables for this program
int cols = 6;
int rows = 8;
unsigned int binary[8] = {0b00000001,0b00000010,0b00000100,0b00001000,0b00010000,0b00100000,0b01000000,0b10000000};

// To be sure
int checkKeys();
void initPins();

int main(void)
{

    initPins();

    //TESTS
    TCCR1B |= (1 << CS10);
    OX(DDRH);
    L(PORTH,PH1);
    //TESTS

    while (1){
        if (TCNT1 >= 49999){
            if (checkKeys() >= 0){
                H(PORTH,PH1);
            }else {
                L(PORTH,PH1);
            }
            TCNT1 = 0;
        }
    }

    return 0;
}

void initPins(){ // Inits all PINs required
    OX(DDRK);
    IX(DDRF);
}

int checkKeys(){ // Returns ID of pressed button (0 - 47)
    for (int x = 0; x < rows; x++){
        S(KEYBOARD_ROW,binary[x]);
        for (int y = 0; y < cols; y++){
            if (GET2(KEYBOARD_COL,binary[y])){
                return (x*cols + y);
            }
        }
    }
    return -1;
}

按下按钮的检测不完整

1 个答案: