Question

我想使用此参数在laravel 4中创建一个路径

$options = [ 'gs_bucket_name' => 'images_upload'];
$upload_url = CloudStorageTools::createUploadUrl('/upload_handler.php', $options);

表示指向此$ upload_url的路由。 createUploadUrl在upload_handler.php上发布帖子并将数据存储到gs bucket。我的问题是没有执行帖子，因为应该在路由上指定upload_url。我怎么能这样做？

upload_handler.php

<?php
var_dump($_FILES);
?>

视图

{{ Form::open(array('action' => 'upload_handler','files' => true)) }}
{{ Form::file('file') }}
<br>
{{ Form::submit('Add Photo', array('class' => 'btn btn-primary' )) }}
{{ Form::close() }}

路线

Route::group(array('before' => 'auth'), function() {
    Route::post('upload_handler', function($upload_url = null) {
        $options = [ 'gs_bucket_name' => 'images_upload'];
        $upload_url = CloudStorageTools::createUploadUrl('/upload_handler.php', $options);
        return $upload_url;
    });
});

但这只是返回网址。怎么做帖子？

在纯php中，代码是：

require_once 'google/appengine/api/cloud_storage/CloudStorageTools.php';

use google\appengine\api\cloud_storage\CloudStorageTools;

$options = [ 'gs_bucket_name' => 'images_upload'];
$upload_url = CloudStorageTools::createUploadUrl('/upload_handler.php', $options);
?>
<div class="body">
    <form action="<?php echo $upload_url ?>" enctype="multipart/form-data" method="post">
        <input type="file" name="uploaded_files" size="40">
        <input type="submit" value="Send">
    </form>
</div>

Answer 1

你的问题有点模糊我害怕，但我认为你所追求的是Redirect::to。这样您就可以将post请求重定向到CloudStorageTools类上方法生成的网址。

return Redirect::to($upload_url);

laravel路由到特定网址

1 个答案: