我正在尝试使用python模块paramiko生成SSH密钥对。有关密钥生成的信息似乎并不多。我已经阅读了paramiko docs,但无法弄清楚什么是错误的。我可以生成没有密码加密的私钥和公钥。但是,当我尝试加密私钥时,我收到以下错误。
ValueError:IV必须长8个字节
我认为上述错误来自pycrypto。我已经查看了paramiko.pkey和pycrypto中的相关代码而没有任何运气。
这是一个小例子。
import paramiko
def keygen(filename,passwd=None,bits=1024):
k = paramiko.RSAKey.generate(bits)
#This line throws the error.
k.write_private_key_file(filename,password = 'cleverpassword')
o = open(fil+'.pub' ,"w").write(k.get_base64())
回溯
Traceback (most recent call last): File "/var/mobile/Applications/149E4C21-2F92-4712-BAC6-151A171C6687/Documents/test.py", line 14, in keygen k.write_private_key_file(filename,password = 'cleverpassword') File "/var/mobile/Applications/149E4C21-2F92-4712-BAC6-151A171C6687/Pythonista.app/pylib/site-packages/paramiko/rsakey.py", line 127, in write_private_key_file self._write_private_key_file('RSA', filename, self._encode_key(), password) File "/var/mobile/Applications/149E4C21-2F92-4712-BAC6-151A171C6687/Pythonista.app/pylib/site-packages/paramiko/pkey.py", line 323, in _write_private_key_file self._write_private_key(tag, f, data, password) File "/var/mobile/Applications/149E4C21-2F92-4712-BAC6-151A171C6687/Pythonista.app/pylib/site-packages/paramiko/pkey.py", line 341, in _write_private_key data = cipher.new(key, mode, salt).encrypt(data) File "/var/mobile/Applications/149E4C21-2F92-4712-BAC6-151A171C6687/Pythonista.app/pylib/site-packages/Crypto/Cipher/DES3.py", line 114, in new return DES3Cipher(key, *args, **kwargs) File "/var/mobile/Applications/149E4C21-2F92-4712-BAC6-151A171C6687/Pythonista.app/pylib/site-packages/Crypto/Cipher/DES3.py", line 76, in __init__ blockalgo.BlockAlgo.__init__(self, _DES3, key, *args, **kwargs) File "/var/mobile/Applications/149E4C21-2F92-4712-BAC6-151A171C6687/Pythonista.app/pylib/site-packages/Crypto/Cipher/blockalgo.py", line 141, in __init__ self._cipher = factory.new(key, *args, **kwargs) ValueError: IV must be 8 bytes long
答案 0 :(得分:3)
这看起来像paramiko
中的错误。
如果您查看在pkey.py
中引发错误的行,则为以下行:
data = cipher.new(key, mode, salt).encrypt(data)
现在让我们看看它之前的行,它首先选择mode
来设置cipher_name
。
# since we only support one cipher here, use it
cipher_name = list(self._CIPHER_TABLE.keys())[0]
cipher = self._CIPHER_TABLE[cipher_name]['cipher']
keysize = self._CIPHER_TABLE[cipher_name]['keysize']
blocksize = self._CIPHER_TABLE[cipher_name]['blocksize']
mode = self._CIPHER_TABLE[cipher_name]['mode']
以下是_CIPHER_TABLE
的内容。
_CIPHER_TABLE = {
'AES-128-CBC': {'cipher': AES, 'keysize': 16, 'blocksize': 16, 'mode': AES.MODE_CBC},
'DES-EDE3-CBC': {'cipher': DES3, 'keysize': 24, 'blocksize': 8, 'mode': DES3.MODE_CBC},
}
观察评论如何与代码相矛盾。有两个密码可用,上面的行选择cipher_name
假设只有一个。
根据错误,似乎选择了'DES-EDE3-CBC'
。如果我们查看DES3.py
中的评论,我们会看到IV的以下要求。
IV : byte string
The initialization vector to use for encryption or decryption.
It is ignored for `MODE_ECB` and `MODE_CTR`.
For `MODE_OPENPGP`, IV must be `block_size` bytes long for encryption
and `block_size` +2 bytes for decryption (in the latter case, it is
actually the *encrypted* IV which was prefixed to the ciphertext).
It is mandatory.
从paramiko的来源,我们发现没有传递IV
,因此我们看到错误。
更改pkey.py
中的以下行,改为对'AES-128-CBC'
密码进行硬编码。
# cipher_name = list(self._CIPHER_TABLE.keys())[1]
cipher_name = 'AES-128-CBC'