Question

我存储的格式为：

网页/网站/ objecthash / xcord / ycord /情形产生/年/月/ datenumber /小时/分钟

现在我有了我想把它们拉出来的水桶。

说我想要最近的10个存储对象。有效的方法是什么？

我有水桶，我该怎么办？

我今天的解决方案是这样的，但是我不确定最近获得的逻辑：

def getKeys():
    b = bucket.list()
    theKeys=[]
    for key in b:
        theKeys.append(key)
    return theKeys

def getDecompiledToday():
    time = datetime.datetime.now()    
    year =time.strftime("%Y")
    month = time.strftime("%m")
    day = time.strftime("%D")
    keys = getKeys()
    objects = []
    for k in keys:
        splitK= k.split("/")
        if splitK[6]==year and splitK[7]==month and splitK[8]==day:
            objets.append(bucket.get_key(k))
    return

Answer 1

我提出的解决方案。

def getPastAmountDecompiledFromFile(number):
    if bucketKeys.__len__() > 0:
        Found=[]
        latest=bucketKeys[0]
        while Found.__len__() < number:
            laterFound = False
            for k in bucketKeys:
                if latest in Found:
                    latest=k
                current = k.split("/")
                best = k.split("/")
                if k not in Found and latest != k:
                    if int(current[6]) > int(best[6]):
                        laterFound=True
                    if int(current[6]) == int(best[6]) and int(current[7]) > int(best[7]):
                        laterFound=True
                    if int(current[6]) == int(best[6]) and int(current[7]) == int(best[7]) and int(current[8]) > int(best[8]):
                        laterFound=True
                    if int(current[6]) == int(best[6]) and int(current[7]) == int(best[7]) and int(current[8]) == int(best[8]) and int(current[9]) > int(best[9]):
                        laterFound=True
                    if laterFound:
                        latest = k
            if laterFound:
                Found.append(latest)
        return getKeyFromKeyNames(Found)
    else:
        getKeysInFile()
        getPastAmountDecompiledFromFile(number)
    return

aws s3 boto按日期检索对象

1 个答案: