查询从SQL Server中的表中检索前两行

Question

我有一个名为Employee的表，其中包含以下字段：

• 的EmpID
• 薪酬
• 名称

我希望获得薪水最高的前两名员工。我该如何撰写此查询？

Answer 1

SQL Server 2000 +：

  SELECT TOP 2
         e.*
    FROM EMPLOYEE e
ORDER BY e.salary DESC

MySQL＆amp; Postgres的：

  SELECT e.*
    FROM EMPLOYEE e
ORDER BY e.salary DESC
   LIMIT 2

甲骨文：

SELECT x.*
  FROM (SELECT e.*,
               ROWNUM as rn
          FROM EMPLOYEE e
      ORDER BY e.salary DESC) x
 WHERE x.rn <= 2

• Oracle: ROW_NUMBER vs ROWNUM

Answer 2

试试这个..

SELECT * from Employee  order by Salary  desc limit 2 ;

Answer 3

SELECT TO 2 * FROM Employee ORDER BY Salary DESC;

Answer 4

你应该写这样的东西。

SELECT TOP 2 EmpID，Salary，Name from Employee ORDER BY Salary

Answer 5

又一个解决方案：

With NumberedItems As
    (
    Select EmpId, Salary, Name
        , Row_Number() Over ( Order By Salary Desc ) As SalaryRank 
    From Employee
    )
Select EmpId, Salary, Name
From NumberedItems
Where SalaryRank <= 2