Question

我有两个java日期时间值，我想知道该过程所需的总时间。

private static Date crawlStartDate,crawlEndDate,totalCrawlTime;

我怎么能得到它？时间格式是yyyyMMddhhmmss

由于

Answer 1

你可以试试这个......

   public static void main(String[] argv) {

    long lStartTime = new Date().getTime(); // start time

    createArray(); // some tasks to eat time

    long lEndTime = new Date().getTime(); // end time

    long difference = lEndTime - lStartTime; // check different

    System.out.println("Elapsed milliseconds: " + difference);

}

public static void createArray() {

    try {
        Thread.sleep(2000);
    } catch (InterruptedException e) {
        e.printStackTrace();
    }

    String sArray[] = new String[1000000];

    for (int i = 0; i < 1000000; i++)
        sArray[i] = "Array " + i;

}

Answer 2

Java解决方案：

long d1=crawlStartDate.getTime()
long d2=crawlEndDate.getTime()
long diff = d2 - d1;
long diffSeconds = diff / 1000 % 60;  
long diffMinutes = diff / (60 * 1000) % 60;

如果您在Linux / BSD中工作，请使用time java MyJavaProcess。 time这里是unix utility。例如，我可以用这种方式测量一些过程：

$ time java Hello
One value
Two value

real    0m0.070s
user    0m0.068s
sys 0m0.000s

Answer 3

在流程执行前获取时间

long t1=crawlStartDate.getTime()

在流程执行后获得时间

long t2=crawlEndDate.getTime()

然后计算差异

long timeDiff=t2-t1;

Date date=new Date(timeDiff);

使用SimpleDateFormat-

格式化它

DateFormat formatet = new SimpleDateFormat("yyyyMMddHHmmss");

String formattedDate= formater.format(date);

Answer 4

enter code here
     String dateStart = "01/14/2012 09:29:58";
    String dateStop = "01/15/2012 10:31:48";
    SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");

    Date d1 = null;
    Date d2 = null;
    try {
     d1= format.parse(dateStart);
     d2 = format.parse(dateStop);
     long diff = d2.getTime() - d1.getTime();
     long diffDays = diff / (24 * 60 * 60 * 1000);
     System.out.print("Days:" + diffDays);
    }catch(Exception e ) {

    }

Answer 5

试试这个

  long differenceInSec = (crawlEndDate.getTime() - crawlEndDate.getTime())/1000;

Answer 6

如果您已更新为JAVA8，请尝试以下代码

LocalDateTime dateTime = LocalDateTime.of(2014, 06, 27, 15, 12);
        LocalDateTime dateTime2 = LocalDateTime.now();

        int diffInNano = java.time.Duration.between(dateTime, dateTime2)
                .getNano();
        long diffInSeconds = java.time.Duration.between(dateTime, dateTime2)
                .getSeconds();

        long diffInMilli = java.time.Duration.between(dateTime, dateTime2)
                .toMillis();
        long diffInMinutes = java.time.Duration.between(dateTime, dateTime2)
                .toMinutes();
        long diffInHours = java.time.Duration.between(dateTime, dateTime2)
                .toHours();
        System.out.println(diffInNano);
        System.out.println(diffInSeconds);
        System.out.println(diffInMilli);
        System.out.println(diffInMinutes);
        System.out.println(diffInHours);

如何在Java中查找进程所花费的总时间

6 个答案: