Question

我已阅读过Laravel文档，但我无法完成这项工作。

有人知道在Eloquent中是否可以进行此查询吗？

如果是这样，你会怎么写呢？

SELECT 

MONTHNAME(postdate) as monthname, 
DATE_FORMAT(postdate,'%m') as month, 
YEAR(postdate) as year, 
COUNT(MONTHNAME(postdate)) as num 

FROM 
postData 

WHERE 
status = 1 

GROUP BY 
monthname,
year 

ORDER BY 
postdate DESC

Answer 1

虽然简单地使用DB::raw进行整个查询确实有效，但对我来说感觉不对。您可能希望使用查询生成器尝试此解决方案。

DB::table('postData')->select([
    DB::raw('MONTHNAME(postdate) AS monthname'),
    DB::raw('DATE_FORMAT(postdate, \'%m\') AS month'),
    DB::raw('YEAR(postdate) AS year'),
    DB::raw('COUNT(MONTHNAME(postdate)) AS num'),
])->where('status', 1)
  ->groupBy('monthname', 'year')
  ->orderBy('postdate', 'DESC');

它仍然使用DB::raw，但仅适用于select子句。无论如何，您可以使用PostData模型而不是DB::table('postData')，但由于它实际上不是常规PostData对象，我建议不要使用它。

Answer 2

如果您不介意使用DB :: raw（），请执行此操作...

轻松复制......

DB :: select（DB :: raw（＆＃34; SELECT MONTHNAME（postdate）作为monthname，DATE_FORMAT（postdate，＆＃39;％m＆＃39;）作为月份，年（postdate）为年，COUNT（MONTHNAME（postdate））为num FROM postData WHERE status = 1 GROUP BY monthname，year ORDER BY postdate DESC＆＃34;））;

一行......

  DB::select(DB::raw("SELECT MONTHNAME(postdate) as monthname, DATE_FORMAT(postdate,'%m') as month,YEAR(postdate) as year, COUNT(MONTHNAME(postdate)) as num FROM postData WHERE status = 1 GROUP BYmonthname,year ORDER BY postdate DESC"));

Laravel中的复杂查询（Eloquent）

2 个答案: