Question

Hibernate不同意这种结构。我错过了什么吗？它引发的错误：

org.hibernate.MappingException：无法找到具有逻辑名称的列：进程中的version_id

有关如何在保持复合键结构的同时进行修复的任何建议？

的DataModel

版本有很多动作

版本有很多流程;

public class Version {
    @Id
    @Column(name = "id")
    public int Id;
}

行动有一个过程

行动有一个版本

public class Action {
    // Action has a composite key (ID and Version ID)

    @Id
    @Column(name = "id")
    public int id;

    @Id
    @ManyToOne
    @JoinColumn(name = "version_id")
    public Version version;

    @ManyToOne
    @JoinColumns({
        @JoinColumn(name = "process_id", referencedColumnName = "id"),
        @JoinColumn(name = "version_id", referencedColumnName = "version_id")
    })
    public Process process;
}

流程有很多动作

流程有一个版本

    public class Process {
    // Process has a composite key (ID and Version ID)

    @Id
    @Column(name = "id")
    public int id;

    @Id
    @ManyToOne
    @JoinColumn(name = "version_id")
    public Version version;

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "process", targetEntity = Action.class)
    public List<Action> actions= new ArrayList<Action>();
}

模特图片： https://dl.dropboxusercontent.com/u/2294873/model.jpg

Answer 1

在Action类中有两列名为version_id的列。尝试将第二个version_id重命名为process_version_id：

public class Action {
    // Action has a composite key (ID and Version ID)

    @Id
    @Column(name = "id")
    public int id;

    @Id
    @ManyToOne
    @JoinColumn(name = "version_id")
    public Version version;

    @ManyToOne
    @JoinColumns({
        @JoinColumn(name = "process_id", referencedColumnName = "id"),
        @JoinColumn(name = "process_version_id", referencedColumnName = "version_id")
    })
    public Process process;
}

Hibernate不接受ManyToOne作为Id

1 个答案: