Question

我是php的新手，希望有人可以提供帮助通过从互联网上提取不同的代码，我已经能够获得RSS源并运行我想要实现的是，如果RSS提要为空，我希望它显示一条消息“当前没有警告”
如果RSS提要中有项目，我希望它显示项目，以及下面设置为隐藏的div。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" dir="ltr" lang="en">
<head>
<title>Weather Warnings for Queensland - Issued by the Bureau of Meteorology</title></head>
<link type="text/css" href="rss-style.css" rel="stylesheet">
</head>
<script type="text/javascript">
    window.setInterval (BlinkIt, 500);
    var color = "#0000FF";
    function BlinkIt () {
        var blink = document.getElementById ("blink");
        color = (color == "#FA000C")? "#0000FF" : "#FA000C";
        blink.style.color = color;
    }
</script>

<body bgcolor="#999">
<h1>Weather Warnings for Queensland - Issued by the Bureau of Meteorology</h1>
<hr>

<br>

<!-- display current weather warnings -->

<fieldset class="rsslib">
<?php
require_once("rsslib.php");
$url = "http://www.bom.gov.au/fwo/IDZ00056.warnings_qld.xml";
    echo RSS_Display($url, 3, false,  true)
     //if there is no warning, i would like to display text saying "There are no current warnings"
    // if there are warnings, I would like it to display the RSS, and also display the below wrapper blinking text.
?>
</fieldset>


<!---------------------------- echo "There are no current weather warnings" ---------------------------------->


<!-- this is where I put my blinking text, this is not currently set to only display when there is a warning-->     

<div id='wrapper' style="display: none">
    <div id="blink">
        Current Weather Warning!
    </div>

    <div id="direction">
        Please go to www.bom.gov.au for more details.
    </div>
</div>

</body>
    </html>

任何帮助都会非常感激，如果需要，我可以复制到rsslib.php中吗？

Answer 1

当您致电RSS_Display时，不要立即显示它，而是将其返回值存储在变量中。然后你可以测试它是否是一个空字符串（无需显示），并采取相应的行动：

$rss = RSS_Display($url, 3, false, true);
if ($rss == '')
{
    // nothing shown, do whatever you want
}
else
{
    // something to display
    echo $rss;
    // you can add other stuff here
}

空RSS源后显示文本

1 个答案: