Question

在我的下面代码中，我将json字符串发布到服务器。虽然我已经写了postParams.add（new BasicNameValuePair（“json_data”，jsonStr））;它给出了参数json_data未传递的错误。

我不确定为什么它会给我错误。

OrderjsonArray.put(order1);
LocationjsonArray.put(location1);
LocationjsonArray.put(location2);
order1.put("locations", LocationjsonArray);

JSONObject ordersObj = new JSONObject();

ordersObj.put("orders", OrderjsonArray);

String jsonStr = ordersObj.toString();

String contentType = "application/json";
List<NameValuePair> postParams = new ArrayList<NameValuePair>();
postParams.add(new BasicNameValuePair("json_data", jsonStr));
HttpGet httpGet = null;
try {
    UrlEncodedFormEntity entity = new UrlEncodedFormEntity(postParams);
    entity.setContentEncoding(HTTP.UTF_8);
    entity.setContentType("application/json");
    httpPost.setEntity(entity);

    httpPost.setHeader("Content-Type", contentType);
    httpPost.setHeader("Accept", contentType);
} catch (UnsupportedEncodingException e) {

}
HttpResponse httpResponse = httpclient.execute(httpPost);

inputStream = httpResponse.getEntity().getContent();

Answer 1

您正在发送json文本作为名称值对的值。但是你的其余代码意味着你必须将它作为multipart formdata发送。显然，服务器也不会查看名称值对。

Answer 2

使用以下代码

try {
                                HttpPost httppost1 = null;
                                HttpClient httpclient1 = new DefaultHttpClient();
                                if (userchk.equalsIgnoreCase("client")) {
                                    httppost1 = new HttpPost(
                                            ApplicationData.serviceURL
                                            + "/clientLogin");
                                } else if (userchk.equalsIgnoreCase("driver")) {
                                    httppost1 = new HttpPost(
                                            ApplicationData.serviceURL
                                            + "/driverLogin");
                                }

                                Log.e("9", "9");

                                // Add your data
                                List<NameValuePair> nameValuePairs1 = new ArrayList<NameValuePair>(
                                        2);
                                nameValuePairs1.add(new BasicNameValuePair(
                                        "vEmail", email.getText().toString()));
                                nameValuePairs1.add(new BasicNameValuePair(
                                        "vPassword", password.getText()
                                        .toString()));

                                httppost1.setEntity(new UrlEncodedFormEntity(
                                        nameValuePairs1));
                                // Execute HTTP Post Request
                                HttpResponse response1 = httpclient1
                                        .execute(httppost1);
                                BufferedReader in1 = new BufferedReader(
                                        new InputStreamReader(response1
                                                .getEntity().getContent()));
                                StringBuffer sb1 = new StringBuffer("");
                                String line1 = "";
                                while ((line1 = in1.readLine()) != null) {
                                    sb1.append(line1);
                                }
                                in1.close();
                                Log.e(userchk + " login original data",
                                        sb1.toString());
                                return sb1.toString();
                            } catch (Exception e) {
                                return "";
                            }

json post httppost参数缺少android

2 个答案: