我有以下代码在asp.net和gridview中创建gridview我有一个删除按钮。下面的代码工作正常,并显示所有行中的删除。 我想隐藏/禁用第一行中的“删除”按钮。有人可以建议代码部分吗?
<asp:gridview ID="Gridview1" runat="server"
ShowFooter="true" AutoGenerateColumns="false">
<Columns>
<asp:BoundField DataField="RowNumber" HeaderText="Row Number" />
<asp:TemplateField HeaderText="Cat">
<ItemTemplate>
<asp:TextBox ID="TextBoxCat" runat="server" Enabled="false"></asp:TextBox>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Delete" >
<ItemTemplate>
<asp:LinkButton ID="DeleteItemsGridRowButton" runat="server">Delete</asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:gridview>
答案 0 :(得分:1)
试试这个:
protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)
{
if(GridView1.Rows.Count>0)
{
//GridView1.Rows[0].Visible = false;
LinkButton DeleteItemsGridRowButton= (LinkButton) GridView1.Rows[0].FindControl("DeleteItemsGridRowButton");
if(DeleteItemsGridRowButton!=null)
{
DeleteItemsGridRowButton.Visible=false
}
}
}
答案 1 :(得分:1)
您可以使用GridView.RowDataBound Event活动。
然后使用 FindControl 方法找到 LinkButton 。
public class Animal
{
public int RowNumber { get; set; }
public string Name { get; set; }
}
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
Gridview1.DataSource = new List<Animal>
{
new Animal {RowNumber = 1, Name = "One"},
new Animal {RowNumber = 2, Name = "Two"},
new Animal {RowNumber = 3, Name = "Three"},
new Animal {RowNumber = 4, Name = "Four"},
};
Gridview1.DataBind();
}
}
private int _counter;
protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
if (_counter == 0)
{
var linkButton = e.Row.FindControl("DeleteItemsGridRowButton")
as LinkButton;
linkButton.Visible = false;
_counter++;
}
}
}