shell_exec命令上的变量Concat

时间:2014-06-27 00:44:54

标签: java php shell-exec

我必须从PHP执行一个jar文件,我必须传递一个参数。

我有这个功能

function sensesOfSentence($sentence){
    $command = sprintf('"C:\Program Files\Java\jre8\bin\java" -jar lesk.jar %s', $sentence);
    return json_decode(shell_exec($command));
}

以这种方式运作

$s = 'the cat and the roof'
echo sensesOfSentence($s);

输出

The command is: "C:\Program Files\Java\jre8\bin\java" -jar lesk.jar the cat and the roof

Array ( [0] => any of several large cats typically able to roar and living in the wild [1] => a protective covering that covers or forms the top of a building )

但是,不是那样的

$owlParsedJson = file_get_contents('owls-dump.php');
$owlParsed = json_decode($owlParsedJson);
echo sensesOfSentence(owlParsed->sentence);

输出

The command is: "C:\Program Files\Java\jre8\bin\java" -jar lesk.jar the cat and the roof

Array ()

当我打印变量命令时,我可以看到正确的句子,但是要正常工作。

0 个答案:

没有答案