我对Eloquent(以及整个ORM)很新。我做了相当多的背景阅读,但不能完全理解Eloquent中的关系。
我有一个与Color模型,Make模型和Model模型相关的Car模型。
我将我的Car :: getAll()传递给我的View作为$ cars。当我打电话给dd(toArray($ cars))时,我得到以下内容:
array (size=1)
0 =>
array (size=12)
'id' => string '1' (length=1)
'registration' => string '123' (length=3)
'make' =>
array (size=5)
'id' => string '1' (length=1)
'title' => string 'Ford' (length=4)
'slug' => string 'ford' (length=4)
'created_at' => string '2014-06-26 21:30:23' (length=19)
'updated_at' => string '2014-06-26 21:30:23' (length=19)
'model' =>
array (size=5)
'id' => string '1' (length=1)
'title' => string 'Mustang' (length=7)
'slug' => string 'mustang' (length=7)
'created_at' => string '2014-06-26 21:30:41' (length=19)
'updated_at' => string '2014-06-26 21:30:41' (length=19)
'color' =>
array (size=5)
'id' => string '1' (length=1)
'title' => string 'Red' (length=3)
'slug' => string 'red' (length=3)
'created_at' => string '2014-06-26 21:30:03' (length=19)
'updated_at' => string '2014-06-26 21:30:03' (length=19)
'year' => string '1991' (length=4)
'is_classic' => string '1' (length=1)
'price' => string '999.00' (length=6)
'sold' => string '0' (length=1)
'active' => string '1' (length=1)
'created_at' => string '2014-06-26 22:17:27' (length=19)
'updated_at' => string '2014-06-26 22:17:27' (length=19)`
这对我来说似乎是正确的,但是当我有:
foreach ($cars as $car) {
echo $car->color-title;
}
我得到了“试图获取非对象的属性”错误。
我的模型如下:
Car.php
class Car extends \Eloquent {
protected $fillable = ['color_id'];
public function color() {
return $this->belongsTo('Color', 'id');
}
public function model() {
return $this->belongsTo('Model', 'id');
}
public function make() {
return $this->belongsTo('Make', 'id');
}
public static function getAll() {
return Car::with('color', 'make', 'model')->where('active', 1)->get();
}
}
Color.php
class Color extends \Eloquent {
protected $fillable = ['title', 'slug'];
public function cars() {
return $this->hasMany('Car', 'color');
}
}
Make.php
class Make extends \Eloquent {
protected $fillable = [];
public function cars() {
return $this->hasMany('Car', 'make');
}
}
Model.php
class Model extends \Eloquent {
protected $fillable = [];
public function cars() {
return $this->hasMany('Car', 'model');
}
}
非常感谢任何帮助。谢谢
修改
抱歉,我应该包含我的架构方法:
CreateMakesTable
public function up()
{
Schema::create('makes', function(Blueprint $table)
{
$table->increments('id');
$table->string('title');
$table->string('slug');
$table->timestamps();
});
}
CreateModelsTable
public function up()
{
Schema::create('models', function(Blueprint $table)
{
$table->increments('id');
$table->integer('make')->unsigned();
$table->string('title');
$table->string('slug');
$table->timestamps();
});
Schema::table('models', function(Blueprint $table)
{
$table->foreign('make')->references('id')->on('makes')->onDelete('cascade');
});
}
CreateColorsTable
public function up()
{
Schema::create('colors', function(Blueprint $table)
{
$table->increments('id');
$table->string('title');
$table->string('slug');
$table->timestamps();
});
}
CreateCarsTable
public function up()
{
Schema::create('cars', function(Blueprint $table)
{
$table->increments('id');
$table->string('registration');
$table->integer('make')->unsigned();
$table->integer('model')->unsigned();
$table->integer('year');
$table->integer('color')->unsigned();
$table->boolean('is_classic');
$table->float('price');
$table->boolean('sold');
$table->boolean('active');
$table->timestamps();
});
Schema::table('cars', function(Blueprint $table)
{
$table->foreign('make')->references('id')->on('makes')->onDelete('cascade');
$table->foreign('model')->references('id')->on('models')->onDelete('cascade');
$table->foreign('color')->references('id')->on('colors')->onDelete('cascade');
});
}
答案 0 :(得分:0)
就像Jason所指出的那样,错误是由其中一个关系返回的null
引起的。但是你的设置问题是,关系定义是错误的。
首先让它们正确:
// it goes like this:
// belongsTo('Model', 'foreign_key_on_this_model', 'primary_key_on_related')
public function color() {
return $this->belongsTo('Color', 'color'); // primary key is id so no need to specify
}
其他模型上的 hasMany
关系没问题。
然后在那个循环中:
foreach ($cars as $car)
{
if (count($car->color))
{
// do something with color
}
}
我之所以使用count
,请阅读:Laravel check if related model exists
您也可以只返回具有相关颜色,制作以及您需要的任何车辆,如下所示:
$cars = Car::has('color')->has('make')...