使用python将列表中的Hex String元素转换为Hex数字或Hex int

Question

skip = 2

with open("text.txt") as f:

    for line in f:

        if line.startswith("blah"):

            next(f)

            lst = [next(f) for i in range(skip)]
            lst = [el.replace('\n', '') for el in lst]
            for i in range(len(lst)/2):
                lst.insert(i,lst.pop(i) + lst.pop(i))
                lst =[int(i,16) for i in lst]
                print lst

我得到了：

lst =[int(i,16) for i in lst]
ValueError: invalid literal for int() with base 16: 'ff 55 00 90 00 92 00 ad 00 c6 00 b7 00 8d 00 98 00 87 00 8a 00 98 00 8f 00 ca 01 78 03 54 05 bf'

任何想法如何获得int hex？

Answer 1

lst =[int(val,16) for line in lst for val in line.split()]

我认为会做你想要的......虽然很难确定