Question

我正在尝试在播放框架中使用光滑，但即使是最简单的示例也要挣扎。

这是我的代码：

case class Account (
  id: Int,
  email: String,
  password: String,
  permission: String
)

class Accounts(tag: Tag) extends Table[Account](tag, "account") {
  def id = column[Int]("id")
  def email = column[String]("email")
  def password = column[String]("password")
  def permission = column[String]("permission")

  def * = (id, email, password, permission)
}

当我编译它时，我收到以下错误：

play.PlayExceptions$CompilationException: Compilation error[No matching Shape found.
Slick does not know how to map the given types.
Possible causes: T in Table[T] does not match your * projection. Or you use an unsupported type in a Query (e.g. scala List).
  Required level: scala.slick.lifted.ShapeLevel.Flat
     Source type: (scala.slick.lifted.Column[Int], scala.slick.lifted.Column[String], scala.slick.lifted.Column[String], scala.slick.lifted.Column[String])
   Unpacked type: models.Account
     Packed type: Any
]

有人能告诉我这里有什么不对吗？

由于

进一步详情：

Scala 2.10
Slick 2.0.2
Play-slick 0.6.0.1
Play Framework 2.3.1

Answer 1

我找到了这个问题。我有一个相互矛盾的伴侣对象

如果您有伴侣对象，则需要对*投影使用略有不同的语法：

def * = (id, email, password, permission) <> ((Account.apply _).tupled, Account.unapply)

Answer 2

根据http://slick.typesafe.com/doc/2.0.2/schemas.html，我认为您的“*”投影方法应如下所示：

def * = (id, email, password, permission) <> (Account.tupled, Account.unapply)

播放框架：Slick不知道如何映射给定的类型

2 个答案: