我目前在做什么:
Invoke-WebRequest -Uri https://coolWebsite.com/ext/ext -ContentType application/json -Method POST -Body $someJSONFile
我正在寻找一种方法在Powershell 中POST这个相同的.json文件而不使用Invoke-WebRequest ,如果可能的话。这个新方法最好允许我获取服务器输出内容并在PowerShell中解析它。
也许通过调用外部cURL方法?我真的不确定,我所有的互联网研究都证明没有结果。
如果没有Invoke-WebRequest,我怎样才能实现上述结果?
答案 0 :(得分:3)
你可以试试这个:
# RestRequest.ps1
Add-Type -AssemblyName System.ServiceModel.Web, System.Runtime.Serialization, System.Web.Extensions
$utf8 = [System.Text.Encoding]::UTF8
function Request-Rest
{
[CmdletBinding()]
PARAM (
[Parameter(Mandatory=$true)]
[String] $URL,
[Parameter(Mandatory=$false)]
[System.Net.NetworkCredential] $credentials,
[Parameter(Mandatory=$true)]
[String] $JSON)
# Remove NewLine from json
$JSON = $JSON -replace "$([Environment]::NewLine) *",""
# Create a URL instance since the HttpWebRequest.Create Method will escape the URL by default.
# $URL = Fix-Url $Url
$URI = New-Object System.Uri($URL,$true)
try
{
# Create a request object using the URI
$request = [System.Net.HttpWebRequest]::Create($URI)
# Build up a nice User Agent
$UserAgent = "My user Agent"
$request.UserAgent = $("{0} (PowerShell {1}; .NET CLR {2}; {3})" -f $UserAgent, $(if($Host.Version){$Host.Version}else{"1.0"}),
[Environment]::Version,
[Environment]::OSVersion.ToString().Replace("Microsoft Windows ", "Win"))
$request.Credentials = $credentials
$request.KeepAlive = $true
$request.Pipelined = $true
$request.AllowAutoRedirect = $false
$request.Method = "POST"
$request.ContentType = "application/json"
$request.Accept = "application/json"
$utf8Bytes = [System.Text.Encoding]::UTF8.GetBytes($JSON)
$request.ContentLength = $utf8Bytes.Length
$postStream = $request.GetRequestStream()
$postStream.Write($utf8Bytes, 0, $utf8Bytes.Length)
#Write-String -stream $postStream -string $JSON
$postStream.Dispose()
try
{
#[System.Net.HttpWebResponse] $response = [System.Net.HttpWebResponse] $request.GetResponse()
$response = $request.GetResponse()
}
catch
{
$response = $Error[0].Exception.InnerException.Response;
Throw "Exception occurred in $($MyInvocation.MyCommand): `n$($_.Exception.Message)"
}
$reader = [IO.StreamReader] $response.GetResponseStream()
$output = $reader.ReadToEnd()
$reader.Close()
$response.Close()
Write-Output $output
}
catch
{
$output = @"
{
"error":1,
"error_desc":"Error : Problème d'accès au serveur $($_.Exception.Message)"
}
"@
Write-Output $output
}
}
2015年10月19日编辑
以下是一个示例用法:
#$urlBase = "http://192.168.1.1:8080/"
#######################################################################
# Login #
#######################################################################
$wsLogin = "production/login"
Function login
{
[CmdletBinding()]
PARAM
(
[ValidateNotNullOrEmpty()]
[String] $login,
[String] $passwd
)
Write-Verbose $wsLogin
#$jsonIn = [PSCustomObject]@{"login"=$login;"passwd"=$passwd} | ConvertTo-Json
$jsonIn = @"
{
"login":"$login",
"passwd":"$passwd"
}
"@
Write-Verbose $jsonIn
$jsonOut = Request-Rest -URL "$urlBase$wsLogin" -JSON $jsonIn -credentials $null
Write-Verbose $jsonOut
#return $jsonOut | ConvertFrom-Json
return $jsonOut
}
答案 1 :(得分:-1)
很容易将该代码转换为cURL
curl -v --insecure -X POST -H“Content-Type:application / json”--data-binary someJSONFile.js https://coolWebsite.com/ext/ext/