Question

好。我一直在处理原始HTTP请求，发现我可以将原始HTTP响应发布到NSLog中，并且我几乎将原始HTTP请求破解为NSLog。我现在只是坚持下去了。

代码示例

   NSString *CurrentWebURL = webView.request.URL.absoluteString;
   NSURLSession *session= [NSURLSession sessionWithConfiguration:[NSURLSessionConfiguration defaultSessionConfiguration]];
   [[session dataTaskWithRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:CurrentWebURL]] completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
   NSDictionary *requestdictionary = [request allHTTPHeaderFields];
   NSLog(@"----shouldStartLoadWithRequest Raw HTTPRequest Start ----");
   for (NSString *Object in [requestdictionary allKeys]) {
         NSLog(@"%@: %@",Object, [requestdictionary objectForKey:Object]);
   }
   NSLog(@"----shouldStartLoadWithRequest Raw HTTPRequest Finish ----"] withlevel:SPECIAL_LOG);

   }]resume];

原始请求：

Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
User-Agent: Mozilla/5.0 (iPad; CPU OS 7_0_6 like Mac OS X)  AppleWebKit/537.51.1 (KHTML, like Gecko) Mobile/11B651

它应该显示我＆＃34;获取：URL＆＃34;，＆＃34;主机＆＃34;，＆＃34;连接：保持活动＆＃34;，＆＃34;接受编码＆＃34 ;，＆＃34;接受＆＃34;，＆＃34; Cookie＆＃34;，＆＃34;连接＆＃34;，＆＃34;接受语言＆＃34;和＆＃34;用户代理＆＃34;。

我的问题是为什么它只显示＆＃34;接受＆＃34;和＆＃34;用户代理＆＃34;？

提出请求：

  NSURL *url = [NSURL URLWithString:PortalURL];

  NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];
  [request setHTTPShouldHandleCookies:YES];
  [request setHTTPMethod: @"GET"];

Fiddler请求跟踪（没有任何自定义标头）：

  GET http://URL/ HTTP/1.1
  Host: Host.co.uk
  Connection: keep-alive
  Accept-Encoding: gzip, deflate
  Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
  Cookie: IsosecCookie=Chris%20Beckett
  Connection: keep-alive
  Accept-Language: en-gb
  User-Agent: Mozilla/5.0 (iPad; CPU OS 7_0_6 like Mac OS X) AppleWebKit/537.51.1 (KHTML, like Gecko) Mobile/11B651

在NSLog中记录请求标头：

  Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
  User-Agent: Mozilla/5.0 (iPad; CPU OS 7_0_6 like Mac OS X) AppleWebKit/537.51.1 (KHTML, like Gecko) Mobile/11B651

Answer 1

我得出的结论是，使用NSURLRequest无法在iOS中获取原始HTTP请求，您只能获得＆＃34;接受＆＃34;和＆＃34;用户代理＆＃34;。

但是我已经完成了一项工作，为了获得原始的HTTP请求，我已经使用了php来获取标题。我知道它不是最好的解决方案，但它很有效，能够记录这些信息，而不必像Fiddler或Charles代理那样继续通过代理。

iOS代码

NSURL *PHPURL = ([NSURL URLWithString:[NSString stringWithFormat:@"http://office.isosec.co.uk/Audit/testRequest.php?"]]);
request = [[NSMutableURLRequest alloc] initWithURL:PHPURL cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:10.0];
[request setHTTPMethod: @"GET"];
[request setHTTPShouldHandleCookies:YES];

NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self startImmediately:NO];

PHPResponse = [NSMutableData data];

if( connection == nil ) {
    [ViewController remoteLog:[NSString stringWithFormat:@"PHPRequest Connection Failed"] withlevel:SPECIAL_LOG];
} else {
    [ViewController remoteLog:[NSString stringWithFormat:@"PHPRequest Connection Started"] withlevel:SPECIAL_LOG];
    [connection scheduleInRunLoop:[NSRunLoop mainRunLoop]
forMode:NSDefaultRunLoopMode];
    [connection start];
}

PHP代码

foreach (getallheaders() as $name => $value) {
    echo "$name: $value,";
}

Answer 2

通过请求任务currentRequest，可以获得实际上已经发送到服务器的URL请求标头，这将为您提供的不仅仅是Accept和{{1至少在我的有限测试中：

User-Agent

修改：不幸的是，它似乎并没有为您提供所有标题，只有__block NSURLSessionDataTask *task = nil; // Use __block because we need to reference this particular pointer, not its current address task = [session dataTaskWithRequest:originalRequest completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) { NSURLRequest *request = task.currentRequest; NSLog(@"Request HTTP Headers: %@", request.allHTTPHeaderFields); }]; [task resume];和Accept-Encoding更多。

HTTP请求标头

2 个答案: