Question

我在从iOS应用程序更新数据库时遇到问题...

Sql语句

<?php

// Create connection
$con=mysqli_connect("server_name","user_name","user_code","table_name");

// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

// This SQL statement selects ALL from the table 'table.name'
$sql = "SELECT * table_name";

// Check if there are results
if ($result = mysqli_query($con, $sql))
{
// If so, then create a results array and a temporary one
// to hold the data
$resultArray = array();
$tempArray = array();

// Loop through each row in the result set
while($row = $result->fetch_object())
{
// Add each row into our results array
$tempArray = $row;
array_push($resultArray, $tempArray);
}

// Finally, encode the array to JSON and output the results
echo json_encode($resultArray); 
}


$sql = "INSERT INTO table_name (column_name) VALUES('1')";


// Close connections
mysqli_close($result);
mysqli_close($con);
?>

我的iOS代码

for (Tickets *items in _feedItems){
if ([resultText.text isEqual:(id) items.ticketNumber]) {

    status.text = @"Match found";

//Contacting database------------------------------

    NSString *strURL = [NSString stringWithFormat:@"TicketDate=%@", items.ticketDate];

    NSData *postData = [strURL dataUsingEncoding:NSASCIIStringEncoding 
allowLossyConversion:YES];
    NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];
    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
    [request setURL:[NSURL URLWithString:@"http://webservice.com"]];
    [request setHTTPMethod:@"POST"];
    [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
    [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-   
Type"];
    [request setHTTPBody:postData];


    NSURLConnection *conn = [[NSURLConnection alloc]initWithRequest:request delegate:self];

    if(conn)
    {
        NSLog(@"Connection Successful");
    }
    else
    {
        NSLog(@"Connection could not be made");
    }

//Contacting database END-------------------------------------------


    break;


}else {

    status.text = @"Match not found";
}
}

我从NSLog获得了一个Connection Succesful，但我的数据库中没有任何更新。

我试图用应用程序手动输入票号，如果它与数据库中的票证匹配（它有效），那么我希望ticketDate从0更改为1。

但它没有改变：/

Answer 1

你没有打电话

[conn start];

有效发送您的请求。即：

NSURLConnection *conn = [[NSURLConnection alloc]initWithRequest:request delegate:self];
[conn start];

您还应该知道请求将以异步发送，这意味着您在调用start后无法立即获得响应。如果要保持异步连接，应该执行的操作是实现data delegate，至少实现– connection:didReceiveData:，– connectionDidFinishLoading:和connection:didFailLoadingWithError:方法。

或者，您可以考虑同步发送请求，即只替换

NSURLConnection *conn = [[NSURLConnection alloc]initWithRequest:request delegate:self];

使用：

[NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

但是这种os请求会阻止您的应用UI，除非您在后台线程上发送它们。

Answer 2

在数据库中，我有一个包含ticketNumber和ticketDate的行。如果我的应用程序中输入的数字与我的数据库中的ticketNumber相同，那么我希望同一行的ticketDate从0更改为1.

无法从iOS应用程序发布到数据库

2 个答案: