表格帮助
ID Name
1 Name1
2 Name2
JSON1 = {name:Name1,data:"data1"}
JSON2 = {name:Name2,data:"data2"}
最终输出表
data reference
JSON1 1
JSON2 2
我希望mysql中的最终输出表引用Table帮助并存储来自JSON1和JSON2的数据
答案 0 :(得分:0)
SELECT "JSON1" AS data,
ID AS reference
FROM Table
WHERE JSON1 LIKE CONCAT('{name:', Name, ',data:%}')
UNION
SELECT "JSON2" AS data,
ID AS reference
FROM Table
WHERE JSON2 LIKE CONCAT('{name:', Name, ',data:%}')