如何搜索文件有一个已知的文件扩展名,如.py ??
fext = raw_input("Put file extension to search: ")
dir = raw_input("Dir to search in: ")
##Search for the file and get the right one's
答案 0 :(得分:4)
我相信你想做类似这样的事情:/dir/to/search/*.extension
?
这叫做glob,以下是如何使用它:
import glob
files = glob.glob('/path/*.extension')
答案 1 :(得分:1)
import os
root="/home"
ext = raw_input("Put file extension to search: ")
path = raw_input("Dir to search in: ")
for r,d,f in os.walk(path):
for files in f:
if files.endswith(ext):
print "found: ",os.path.join(r,files)
答案 2 :(得分:0)
非递归:
for x in os.listdir(dir):
if x.endswith(fext):
filename = os.path.join(dir, x)
# do your stuff here
答案 3 :(得分:-1)
你可以写的很简单:
import os
ext = raw_input("Put file extension to search: ")
path = raw_input("Dir to search in: ")
matching_files = [os.path.join(path, x) for x in os.listdir(path) if x.endswith(ext)]