Question

是否可以在Python上创建一个字典，用循环插入列表和值？

说我有两个看起来像这样的列表

for i in holders:
    print(i)

...给出

[1, 1]
[1, 2]
[1, 3]
[1, 4]
[2, 1]
[2, 2]
[2, 3]
[2, 4]
[3, 1]
[3, 2]
[3, 3]
[3, 4]
[4, 1]
[4, 2]
[4, 3]
[4, 4]
[5, 1]
[5, 2]
[5, 3]
[5, 4]

和另一个

for row in myArray:
    print(row)

['0.0', '0.0', 'NaN']
['1.0', '0.0', '1.0']
['2.0', '0.0', 'NaN']
['3.0', '0.0', 'NaN']
['0.0', '1.0', '2.0']
['1.0', '1.0', '3.0']
['2.0', '1.0', '4.0']
['3.0', '1.0', 'NaN']
['0.0', '2.0', '5.0']
['1.0', '2.0', '6.0']
['2.0', '2.0', '7.0']
['3.0', '2.0', 'NaN']
['0.0', '3.0', 'NaN']
['1.0', '3.0', 'NaN']
['2.0', '3.0', '8.0']
['3.0', '3.0', '9.0']
['0.0', '4.0', 'NaN']
['1.0', '4.0', 'NaN']
['2.0', '4.0', 'NaN']
['3.0', '4.0', '10.0']

我想在python中编写一个类似于

的字典

Diction = 
    { '[1,1]': '-1'
      '[1,2]': '1'

......等等如果第3行是NaN，我想写-1 如果它是一个真实的数字而不是我写的那个数字..

这有道理吗？我花了几个小时思考和尝试，没有运气

Answer 1

你可以写：

my_dict = {str(h):l[-1] if l[-1] is not 'NaN' else '-1' for h, l in zip(holders, myArray)}

此外，您应避免使用myArray等标识符 - camelCase为considered bad Python style。

这会在用作密钥的字符串化列表中为您提供额外的空间，但我怀疑这不值得取出（即如果您打算检查其他字符串列表中的密钥，它会＆＃39;我会为你创造更多的工作。）

Answer 2

l = [[1, 1],[1, 2],[1, 3]]

l2= [['0.0', '0.0', 'NaN'],['1.0', '0.0', '1.0'],['2.0', '0.0', 'NaN'],['3.0', '0.0', 'NaN']]

d = {}
for k,v in zip(l,l2):
    if v[-1] == "NaN":
       d[str(k)] = '-1'
    else:
        d[str(k)] = v[-1]

{'[1, 2]': '1.0', '[1, 1]': '-1', '[1, 3]': '-1'}

在Python中制作字典

2 个答案: