我有这个脚本:
<script>
function $(id) {
return document.getElementById(id);
}
function getImage() {
$('loader').src='/misc/images/loading.gif';
var url = "http://mousecreator.com/";
// outfit
var head = "&head="+$('head').value;
var ears = "&ears="+$('ears').value;
var eyes = "&eyes="+$('eyes').value;
var mouth = "&mouth="+$('mouth').value;
var neck = "&neck="+$('neck').value;
var ears = "&ears="+$('ears').value;
var hair = "&hair="+$('hair').value;
var fur = "&fur="+$('fur').value;
var tail = "&tail="+$('tail').value;
// sham
if(document.sh.sham.checked)
var sham = "&sham=1";
else
var sham = "";
//alert(document.sh.sham.checked);
var murl = url +"mouse.php?" + head + ears + eyes + mouth + neck + ears + hair + fur + tail + sham;
// set the preview image and text box
$('prem').src=murl;
}
function remLoad() {
$('loader').src="";
}</script>
<select id="head">
<option value="235">Value 1</option>
<option value="324">Value 2</option>
...
...
<button onclick="getImage()">Generate</button>
有没有办法在单击Generate按钮的同时使按钮从所有下拉列表中随机选择id?每个id(头部,耳朵,眼睛等都有它自己的下载列表)
提前致谢!
答案 0 :(得分:1)
function randomItemFrom(arr) {
return arr[Math.floor(Math.random() * arr.length)];
}
function randomOptionFrom(select) {
return randomItemFrom(select.options);
}
var randomEye = randomOptionFrom($('#eyes')[0]).value;
您还可以使randomOptionFrom
函数接受jQuery对象或选择器。
function randomOptionFrom(select) {
return randomItemFrom($(select)[0].options);
}
然后你可以这样称呼它:
randomOptionFrom($('#eyes')).value;
或
randomOptionFrom('#eyes').value;