使用php导致嵌套的json

Question

我希望SO会帮助我。在过去的几天里，我一直在尝试处理查询但没有得到正确的解决方案。 我的查询如下

    $sql =  "SELECT 
            m.MarkID, m.studentID, 
            sm.ExamName, sb.Subject, 
            sm.MaxMarks, m.MarksRecvd  

            FROM marks AS m

            RIGHT JOIN student AS st 
            ON m.studentID=st.studentID

            RIGHT JOIN semester AS sm
            ON m.ExamID=sm.ExamID

            RIGHT JOIN subject AS sb 
            ON m.SubjectID=sb.SubjectID

            WHERE m.studentID = $studentID
            ORDER BY ExamName ASC";


    $sql = $con->prepare($sql);
    $sql->execute();
    $rows = array();

    while ($row = $sql->fetch(PDO::FETCH_OBJ)) {
        $rows['data'][] = $row;
    }

    echo json_encode($rows, JSON_NUMERIC_CHECK);

这导致json：

{"data":[
{"MarkID":22,"studentID":2,"ExamName":"Semester-1","Subject":"Sports","MaxMarks":100,"MarksRecvd":45},

{"MarkID":20,"studentID":2,"ExamName":"Semester-1","Subject":"Science","MaxMarks":100,"MarksRecvd":15},

{"MarkID":21,"studentID":2,"ExamName":"Semester-2","Subject":"Social Science","MaxMarks":100,"MarksRecvd":25}]}

并输出到表格如下：

但是需要帮助以获得如下所示的json响应：

{"data":        
"studentID":2
[
    {

    "Subject":"Sports",
    "Result":
            [
                {
                "ExamName":"Semester-1",
                "MaxMarks":100,
                "MarksRecvd":15
                },
                {
                "ExamName":"Semester-2",
                "MaxMarks":100,
                "MarksRecvd":29
                }
            ]
    "Subject":"Science",
    "Result":
            [
                {
                "ExamName":"test-1",
                "MaxMarks":10,
                "MarksRecvd":8
                },
                {
                "ExamName":"Semester-2",
                "MaxMarks":100,
                "MarksRecvd":84
                }
            ]

    }
]}

如果可能，请使用json指向CRUD多对多数据库的好文章

我正在尝试复制如下表格：