我的EXCEL文件格式
Name Gender DateofBirth HomeZipcode CoverageTier
----------------------------------------------------------
Test1 F 1966-07-21 78201 Fam
Test2 M 1966-07-21 78201 E
使用以下代码转换
System.Data.OleDb.OleDbConnection MyConnection;
System.Data.DataSet ds;
System.Data.OleDb.OleDbDataAdapter MyCommand;
MyConnection = new System.Data.OleDb.OleDbConnection("provider=Microsoft.ACE.OLEDB.12.0;Data Source='C:/Users/guru/Desktop/CensusData2013.xlsx';Extended Properties=Excel 12.0;");
MyCommand = new System.Data.OleDb.OleDbDataAdapter("select * from [Test$]", MyConnection);
MyCommand.TableMappings.Add("Table", "Member");
ds = new System.Data.DataSet("Members");
MyCommand.Fill(ds);
MyConnection.Close();
string path = Server.MapPath("CensusData.xml");
ds.WriteXml(path);
我当前的XML输出格式
<?xml version="1.0" standalone="true"?>
<Members>
<Member>
<Name>Test1</Name>
<Gender>F</Gender>
<DateofBirth>1966-07-21T00:00:00+05:30</DateofBirth>
<HomeZipcode>78201</HomeZipcode>
<CoverageTier>Fam</CoverageTier>
</Member>
<Member>
<Name>Test2</Name>
<Gender>M</Gender>
<DateofBirth>1966-07-21T00:00:00+05:30</DateofBirth>
<HomeZipcode>78202</HomeZipcode>
<CoverageTier>E</CoverageTier>
</Member>
</Members>
我需要添加excel文件
Location
LX
对所有用户来说都很常见,例如Test1,Test2
现在我需要在xml中获得以下结果
<?xml version="1.0" standalone="true"?>
<Members>
<CompanyLocation>
<Location>LX</Location>
</CompanyLocation>
<Member>
<Name>Test1</Name>
<Gender>F</Gender>
<DateofBirth>1966-07-21T00:00:00+05:30</DateofBirth>
<HomeZipcode>78201</HomeZipcode>
<CoverageTier>Fam</CoverageTier>
</Member>
<Member>
<Name>Test2</Name>
<Gender>M</Gender>
<DateofBirth>1966-07-21T00:00:00+05:30</DateofBirth>
<HomeZipcode>78202</HomeZipcode>
<CoverageTier>E</CoverageTier>
</Member>
</Members>
如何获得如上所述的xml输出。