Question

嗨，我有这个程序：

import java.util.Scanner;

public class HowAreYou {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String input;

        System.out.println("How are you?");
        input = in.nextLine();
        if (input.equals("I'm doing good!")) {
            System.out.print("That's great to hear!");
        } else if (input.equals("I'm not doing too well...")) {
            System.out.print("Aw I'm sorry to hear that");
        } else {
            System.out.print("Sorry I didn't catch that are you doing good or bad?");
            input = in.nextLine();
            if (input.equals("good")) {
                System.out.print("That's great to hear!");
            } else if (input.equals("bad")) {
                System.out.print("Aw I'm sorry to hear that");
            }
        }

    }
}

它适用于前两个回复，如果你输入的内容不是那么打印＆＃34;抱歉，我没有抓到你做得好不好？＆＃34;正确，但我希望它在打印后再次收到响应。在它说完之后的那一刻＆＃34;抱歉，我没有抓到你做得好还是坏？＆＃34;它不允许你输入任何其他东西。

Answer 1

只需使用无限循环。像这样的东西

while(true){

  // your code here...

  if(input.equals("exit")) break; 

}

这是最简单的解决方案。

Answer 2

您可以通过添加while循环来完成此操作。

import java.util.Scanner;

public class HowAreYou {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String input;

        /* loop which keeps asking for input  ends when user enters Bye Bye*/
        while(true){ 

        System.out.println("How are you?");
        input = in.nextLine();
        if (input.equals("I'm doing good!")) {
            System.out.println("That's great to hear!");
            break;
        } else if (input.equals("I'm not doing too well...")) {
            System.out.println("Aw I'm sorry to hear that");
            break;
        } else if (input.equals("Bye Bye")) {
            System.out.println("Bye Bye");
            break;
        } else {
            System.out.println("Sorry I didn't catch that are you doing good or bad?");
        }
      }
    }
}

Answer 3

我认为您遇到的问题是，在"Sorry I didn't catch that are you doing good or bad?"消息后，您点击enter key以提供响应并且您的程序终止。发生这种情况是因为input.nextLine消耗了它，并且它与任何内容都不匹配，并且您的程序退出。

你应该替换

System.out.print("Sorry I didn't catch that are you doing good or bad?");

与

System.out.println("Sorry I didn't catch that are you doing good or bad?");

这样你就可以在实际输入之前到达下一行。希望这会有所帮助。

简单的java AI响应程序？

3 个答案: